c，将struct作为参数传递

Question

I need to pass some structure as function argument like this

void myFunc(unsigned char c);

I will use myFunc(4) , myFunc(8) or so.

Now the function accepts a structure as argument, so I tried

typedef struct {
    unsigned char address;
    unsigned char command;
    unsigned char group;
    unsigned char response;
    unsigned char flags1;
    unsigned char flags2;
}test_t;

void myFunc(test_t test);

myFucn({0,0,0,0,0}); // but this gives me error 

How can I pass const struct as argument without to have to instantiate first ? Just like myFunc(4) as unsigned char.

Thanks

Answer 1

In C99, you can use a compound literal :

myFunc((test_t) { 0, 0, 0, 0, 0 });

Of course, since the struct is being passed by value, it doesn't matter if you consider it to be "const" or not; whatever the function does to it won't matter to the outside.

In previous versions of C, you cannot do this.