jQuery搜索替换字符串

Question

I'm trying to rename some fields in a clone function, but I'm not sure how to rename (increase) the field name.

var tr = $copy.clone();
tr('input').each(function() {
  console.log(this.name); 
  this.name = something;
});

Example of field name:

field[subform][0][subsubform][2][name]

In this case I would need to increase [2] to [3] . The name could have more or less brackets, but it's always the second last one that I would need to increase.

How do I go about doing this?

Answer 1

Assuming it will always precede a [...] at the end of the string:

name.replace(/\[(\d+)\](\[[^\[]+\])$/, function (pattern, value, tail) {
    return "[" + (parseInt(value, 10) + 1) + "]" + tail;
});​

Answer 2

You can do it like this if it is always the second last one

var name = 'field[subform][0][subsubform][2][name]';
var firstStr = name.split('][').slice(0,-2);
var secStr = name.split('][').slice(-2);
secStr[0] = +secStr[0] +1; 
console.log(firstStr.concat(secStr).join(']['));

http://jsfiddle.net/3TuHg/

or like this

var name = 'field[subform][0][subsubform][2][name]';
var str = name.split('][');
str[str.length - 2] = +str[str.length - 2] + 1;
str = str.join('][');
console.log(str);

http://jsfiddle.net/NsGvv/

Answer 3

Using indexOf and substr .

The following code gets the first part of the string before the number, the number, and the string after the number. Then add 1 to the number and concat everything.

var string = "field[subform][0][subsubform][2][name]",
    beg = string.indexOf("subsubform][") + 12,
    end = string.indexOf("]", beg);
string = string.substr(0, beg) + (parseInt(string.substr(beg, end)) + 1) + string.substr(end);

demo

Answer 4

Regular expression fun. Matches a pattern [number][string]end Of line, reads the number, adds one, joins other part of match, and sets the new name.

$(tr).find("input").prop("name", function() {
    return this.name.replace(
        /\[(\d+)(\]\[[^[]+]$)/,
        function (a,b,c) { 
            return "[" + (parseInt(b,10)+1) + "]" +  c;
        }
    )
});