在Python 3.3中从字符串创建列表

Question

I have a string like this (with n number of elements):

input = 'John, 16, random_word, 1, 6, ...'

How can I convert it to a list like this? I would like ',' to be a separator.

output = [John, 16, random_word, 1, 6, ...]

Answer 1

You can use input.split(',') but as others have noted, you'll have to deal with leading and trailing spaces. Possible solutions are:

• without regex:

   In [1]: s = 'John, 16, random_word, 1, 6, ...' In [2]: [subs.strip() for subs in s.split(',')] Out[2]: ['John', '16', 'random_word', '1', '6', '...'] 

  What I did here is use a list comprehension , in which I created a list whose elements are made from the strings from s.split(',') by calling the strip method on them. This is equivalent to

   strings = [] for subs in s.split(','): strings.append(subs) print(subs) 

• with regex :

   In [3]: import re In [4]: re.split(r',\\s*', s) Out[4]: ['John', '16', 'random_word', '1', '6', '...'] 

Also, try not to use input as variable name, because you are thus shadowing the built-in function .

You can also just split on ', ' , but you have to be absolutely sure there's always a space after the comma (think about linebreaks, etc.)

Answer 2

you mean output = ['John', '16', 'random_word', '1', '6', ...] ? you could just split it like output = inpt.split(', ') . this also removes the whitespaces after , .

Answer 3

使用分割功能。

output = input.split(', ')

Answer 4

If I understand correctly, simply do:

output = input.split(',')

You will probably need to trim each resulting string afterwards since split does not care about whitespaces.

Regards, Matt