[英]C++ Boost: Split function is_any_of()
I'm trying to use the split()
function provided in boost/algorithm/string.hpp
in the following function : 我正在尝试在以下函数中使用
boost/algorithm/string.hpp
中提供的split()
函数:
vector<std::string> splitString(string input, string pivot) { //Pivot: e.g., "##"
vector<string> splitInput; //Vector where the string is split and stored
split(splitInput,input,is_any_of(pivot),token_compress_on); //Split the string
return splitInput;
}
The following call : 以下电话:
string hello = "Hieafds##addgaeg##adf#h";
vector<string> split = splitString(hello,"##"); //Split the string based on occurrences of "##"
splits the string into "Hieafds" "addgaeg" "adf"
& "h"
. 将字符串分成
"Hieafds" "addgaeg" "adf"
和"h"
。 However I don't want the string to be split by a single #
. 但是我不希望字符串被单个
#
拆分。 I think that the problem is with is_any_of()
. 我认为问题在于
is_any_of()
。
How should the function be modified so that the string is split only by occurrences of "##"
? 如何修改函数,以便只通过出现
"##"
来拆分字符串?
You're right, you have to use is_any_of() 你是对的,你必须使用is_any_of()
std::string input = "some##text";
std::vector<std::string> output;
split( output, input, is_any_of( "##" ) );
update 更新
But, if you want to split on exactly two sharp, maybe you have to use a regular expression: 但是,如果你想分成两个尖锐的,也许你必须使用正则表达式:
split_regex( output, input, regex( "##" ) );
take a look at the documentation example . 看一下文档示例 。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.