[英]How to hide form from taskbar in c++ builder?
I have simple VCL Forms application which on start show on taskbar button if is in use, what i want to do is to hide those button, so that mean whatever is happen with form that those button don't appear. 我有简单的VCL Forms应用程序,如果正在使用,在任务栏按钮上开始显示,我想要做的是隐藏那些按钮,这意味着那些按钮不出现的形式发生的任何事情。 Case can be that forms is shown or hidden or any other but button have to be hidden, how to do that?
案例可以是显示或隐藏的表格或任何其他但必须隐藏按钮,如何做到这一点?
PS I see that question like this exist but they don't work in my cause. PS我看到这样的问题存在,但它们在我的事业中不起作用。
Try the following approach: 尝试以下方法:
Source: http://delphi.about.com/od/delphitips2008/qt/hide_taskbutton.htm 资料来源: http : //delphi.about.com/od/delphitips2008/qt/hide_taskbutton.htm
Not only did I have to do what Spook answered, but also (thanks to http://codeverge.com/embarcadero.cppbuilder.ide/builder-c++-xe-and-hiding-taskbar/1073223 ) 我不仅要做Spook的回答,而且还要感谢http://codeverge.com/embarcadero.cppbuilder.ide/builder-c++-xe-and-hiding-taskbar/1073223
void __fastcall TForm1::FormCreate(TObject *Sender)
{
Application->MainFormOnTaskBar = false;
DWORD dwExStyle = GetWindowLong(Application->Handle, GWL_EXSTYLE);
dwExStyle &= ~WS_EX_APPWINDOW;
dwExStyle |= WS_EX_TOOLWINDOW;
SetWindowLong(Application->Handle, GWL_EXSTYLE, dwExStyle);
}
void __fastcall TForm1::FormActivate(TObject *Sender)
{
ShowWindow(Application->Handle, SW_HIDE);
}
//---------------------------------------------------------------------------
void __fastcall TForm1::CreateParams(TCreateParams &Params)
{
TForm::CreateParams(Params);
Params.ExStyle &= ~WS_EX_APPWINDOW;
Params.ExStyle |= WS_EX_TOOLWINDOW;
}
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