如何使用C＃和/或Notepad ++在文本行的开头添加连续数字？

Question

I basically have a whole list of data that looks like this:

text', 0, 16, 0, 160),
text text', 0, 36, 0, 720),
text text text', 6, 14, 200, 400),
text text', 6, 20, 40, 185),
text text text text', 6, 6, 80, 80),
text text', 0, 18, 0, 260),
text text text', 3, 3, 60, 60),

I need this to look like this:

(1444, text text', 0, 36, 0, 720),
(1445, text text text', 6, 14, 200, 400),
(1446, text text', 6, 20, 40, 185),
(1447, text text text text', 6, 6, 80, 80),
(1448, text text', 0, 18, 0, 260),
(1449, text text text', 3, 3, 60, 60),

So I basically wrote a for loop in C# to generate the numbers:

 for(int i =0; i < amount; i ++)
        {
            Console.WriteLine("("+counter+",");
            counter++;
        }

Counter being the numbers I need and amount being the amount of times I need numbers generated.

I am trying to figure out how to get "(1111," in front of "text', 0, 0, 0, 0)," per each line, I was trying to find and replace in notepad but I couldn't get it to work, is there a way I could do the whole thing in C#? Or any other way at all?

Answer 1

var indexedLines = yourData.Select((line, idx) => new {Line = line, Index = idx});

foreach(var indexedLine in indexedLines)
    Console.WriteLine("({0}, {1}", indexedLine.Index, indexedLine.Line);

Answer 2

您不能只使用Excel或其他电子表格处理器吗？

Answer 3

Yes, use the following resource: http://msdn.microsoft.com/en-us/library/ezwyzy7b.aspx

And try doing something like:

Console.Writeline("(" + counter + "," + line);