Android：强制线程关闭并显示警报对话框

Question

I have a thread inside which I catch an exception. What I want is that when this happens, the thread closes/quits/dies or whatever I should say, and an alert dialog is displayed (no like toasts!).

Here's my code:

    t1 = new Thread(new Runnable()
    {   
        public void run() 
        {
            Looper.prepare();
            StringBuffer stringBuffer = new StringBuffer("");
            BufferedReader bufferedReader = null;
            URI uri = null;

            try
            {
                requestAndMakeSheet(stringBuffer, bufferedReader, uri);
            }
            catch (Exception e)
            {
                //Toast.makeText(getBaseContext(), "Web Request Error", Toast.LENGTH_LONG).show();
                //Log.e("Web Request Error", e.getMessage());
                t1.interrupt();
                AlertDialog.Builder parsingErrorBox = new AlertDialog.Builder(ReservationInfo.this);
                parsingErrorBox.setTitle("Login error");
                parsingErrorBox.setMessage("You may have to check your credentials and then try again.");
                parsingErrorBox.show();
            }
            finally
            {
                if (bufferedReader!=null)
                {
                    try
                    {
                        bufferedReader.close();
                    }
                    catch (IOException ioe)
                    {
                        Log.e("Web Request Error", ioe.getMessage());
                    }
                }
            }
        }           
    });
    t1.start();
    try 
    {
        t1.join();
        mWebview.loadUrl("file:///"+Environment.getExternalStorageDirectory()+"/MySheet.html");
        setContentView(mWebview);
    } 
    catch (InterruptedException e) 
    {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    //End of le thread
}

This code crashes, I think it has something to do with t1.interrupt (tried stop instead, but didn't work either).

How can I fix this code? Thank you in advance.

Answer 1

Why do you have the t1.interrupt() anyway? Seems like your thread will be terminated regardless so what is the reason for putting it there?