[英]Closures and callbacks
I'm working on a database function and need to return results from fetchAll so I can use it elsewhere in my code but am not sure how to do it: 我正在研究数据库函数,需要从fetchAll返回结果,所以我可以在我的代码中的其他地方使用它,但我不知道该怎么做:
function fetchAll(sql,params,tableref){
var fields = new Array();
var resultout = new Array();
for (i in tableref){
fields.push(i);
}
getResults(sql,params,fields,function(results){
// I WANT TO RETURN RESULTS
resultout.push(results);
});
// TO HERE SO I CAN RETURN from Fetchall
console.log(resultout);
}
function getResults(query,params,fields,callBack){
var result = new Array();
thisDB.transaction(function (tx) {
tx.executeSql(query,params, function(tx, rs){
for(var i=0; i<rs.rows.length; i++) {
var row = rs.rows.item(i);
var rowresults = new Object();
for (x=0;x<fields.length;x++){
rowresults[fields[x]] = row[fields[x]];
}
result.push(rowresults);
}
callBack(result);
});
});
return result;
}
I think i'm missing something obvious. 我想我错过了一些明显的东西。
Thanks 谢谢
Antony 安东尼
If I'm understanding correctly your question, to see the result you need this 如果我正确理解你的问题,要看到你需要的结果
function fetchAll(sql,params,tableref){
var fields = new Array();
var resultout = new Array();
for (i in tableref){
fields.push(i);
}
getResults(sql,params,fields,function(results){
// I WANT TO RETURN RESULTS
resultout.push(results);
console.log(resultout);
});
}
The callback will be executed "after" so basically in your example you'd see an empty result. 回调将在“之后”执行,所以基本上在你的例子中你会看到一个空结果。 This is because of the asynchronous nature of the callback.
这是因为回调的异步性质。
I think you are trying to move from an asynchronous request to a synchronous one 我认为您正在尝试从异步请求转移到同步请求
Is a good topic, you can find many posts and solutions addressing this on the web 这是一个很好的主题,您可以在网上找到许多解决此问题的帖子和解决方案
You have several options: 你有几个选择:
Use callback instead return in your function: Your function must receive another param (the callback) and call that callback passing to it the value that you want to return 使用回调代替函数返回:你的函数必须接收另一个参数(回调)并调用该回调传递给你想要返回的值
function fetchAll (sql, params, tableref, callback) { var fields = new Array(); for (i in tableref) { fields.push(i); } getResults(sql, params, fields, function (results) { // I WANT TO RETURN RESULTS callback(results); }); }
Then you can log the results like this: 然后你可以像这样记录结果:
fetchAll(sql, params, tableref, function (results) { console.log(results); });
Find a synchronous version of getResults
, often there is one function for that, maybe getResultsSync
? 找到
getResults
的同步版本,通常有一个函数,也许getResultsSync
?
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