如何使用正则表达式找出Python列表中是否有任何一项在字符串中？

Question

I have a list and I'd like to find out if any one item in that list is in a string using regex. Is there a way to do this?

Answer 1

Sure.

myregex = re.compile(...)
print any(myregex.search(s) for s in my_list_of_strings)

or maybe:

regexs = [re.compile(s) for s in my_list_of_regex_strings]
any(r.search(my_string) for r in regexs)

which I suppose is probably the same thing as :

regex_str = '|'.join('(?:%s)'%re.escape(s) for s in list_of_regex_strings)
re.search(regex_str,my_string)

I still can't tell which way you're trying to go with this...

Finally, if you actually want to know which regex matched:

next(regex_str for regex_str in regex_str_list if re.search(regex_str,mystring))

This will raise a StopIteration exception (that you can catch) if none of the regex's match.

Answer 2

I'm assuming that OP is asking how to to find out if any one item in a list of strings matches a pattern using regex .

# import the regex module
import re

# some sample lists of strings
list1 = ['Now', 'is', 'the', 'time', 'for', 'all', 'good', 'men']
list2 = ['Me', 'Myself', 'I']

# a regex pattern to match against (looks for words with internal vowels)
pattern = '.+[aeiou].+'

# use any() around a list comprehension to determine
# if any match via the re.match() function
any(re.match(pattern, each) for each in list1)

# if you're curious to determine just what is matching your expression, use filter()
list(filter(lambda each: re.match(pattern, each) , list2))

Answer 3

for each item in list:
   use regex on string

thats as specific as possible given the generalistic nature of your question.

EDIT: this is psuedocode, not python