使用jQuery我们如何从值为false的所有元素中删除disabled属性？

Question

I have input checkboxes printed like the following.

<input type="checkbox" id="a1" value="11" disabled="false">
<input type="checkbox" id="a2" value="21" disabled="true">
<input type="checkbox" id="a3" value="31" disabled="false">

I know the disabled attribute takes no value. So when the attribute is present the element becomes disabled irrespective of the value assigned to it. I want to remove all the disabled attribute from all input elements whose value is false.

Using jQuery I would like to use code like the following.

$("*[disabled]").not(true).removeAttr("disabled");

Answer 1

Why don't you just match elements where disabled is false ?

$('[disabled="false"]​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​')​.removeAttr('disabled');​​​

Demo: http://jsfiddle.net/ASN29/

The presence of the disabled attribute automatically makes the element disabled, regardless of the attribute's value, so this isn't a very good idea. How does the HTML become this way?

Answer 2

You could simply use a selector like this:

$('input[disabled="false"]').removeAttr("disabled");

jsFiddle Demo

Instead of * , I added input , it narrows the query down a lot. This will search for input elements that have an attribute called disabled having the value false .

I would suggest you don't do this at all. That HTML should have never been generated.

Answer 3

If you want to enabled them use the .prop() instead .. ( that is because disabled as an actual property of checkbox inputs )

$('input[disabled="false"]').prop('disabled', false);

Demo at http://jsfiddle.net/gaby/Bn4dr/

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The correct way, though, would be to print the proper html directly

<input type="checkbox" id="a1" value="11">
<input type="checkbox" id="a2" value="21" disabled>
<input type="checkbox" id="a3" value="31">

Answer 4

​$(document).ready(function (){
    $('input:disabled').removeAttr('disabled');    
});​

Here is the jsFiddle for it and documentation on :disabled selector

Answer 5

$('input[disabled="false"]').removeAttr("disabled");

See http://jsfiddle.net/JKs4C/

As to whether this is a good idea, on the other hand... I think the real answer is to fix up your server-side rendering to omit the disabled attribute entirely for elements that aren't disabled. Otherwise you'll end up with all elements disabled if your scripts go wrong, noscript, etc.