如何排序地图 <String, List<Object> &gt;通过分配给它的最多值（不是数字）的键

Question

I have been working with Maps at present and I am baffled by how I can get my program to work effectively. I can iterate over the map get the keys and values and sort them in alphabetical and reverse alphbetical order quite easily and have used custom comparators for this. However, I am now trying to sort the map based on the key with the most values. The values are a list of objects I have created and can be thought of as this scenario.

There is an Atlas(like a catalog) that has lots of towns (the key of type string). That contains Shops(List). I want to sort this so that the town with the most shops is displayed first and goes in descending order with the secondary sorting being based on town alphabetically and return a string representing this.

I have used the Comparator interface with seperate classes for each one alphabetically and reverse alphabetically so far and wish to follow the same pattern for learning purposes However this has me completely stumped.

Example:

class Atlas {

       Map<String, List<Shop> atlas = new HashMap<String, List<Shop>();

       void addShop(Shop shop){
            //if(Atlas already contains){
              get the town and add the shop to it.
            }
            else{
                 add the town as the key and the shop as the value in the list
            }
       }

       List<Shop> getAllShopsFromTheGivenTown(String givenTown){
            //if(Atlas contains givenTown){
            return the givenTown from the List. 
            }
            else{
                 //Return an ArrayList emptyList
            }
       }

       public String returnAllTownsAndShopsAlphbetically(){
       String tmpString = "";   

    List<String> keys = new LinkedList<String>(atlas.keySet());
    TownComparatorAtoZ tc = new TownComparatorAtoZ();
    Collections.sort(keys, tc);

    for(String town : keys){
         List<Shop> shops = new LinkedList<Dealer>(atlas.get(town));
         ShopComparatorAtoZ sc = new ShopComparatorAtoZ();
          Collections.sort(shop, sc);

        for(Shop shop : shops){
            if(tmpString.isEmpty()){
            tmpString = tmpString + town + ": " + shop.getName();
            }
            else if(tmpString.contains(town)){
            tmpString = tmpString + ", " + shop.getName();
            }
            else{
            tmpString = tmpString + " | " + town + ": " + shop.getName();               }   
        }
    }       
    return tmpString;   
    }
}

As can be seen from above (although not the cleanest and most efficient) returns things alphabetically and will be reformatted into a string builder. However, I am wondering how I can use a comparator to achieve what I am after and if someone could provide a code snippet with an explanation of what it actually does I would be grateful as its more about understanding how to do it not just getting a copy and pasted lump of code but need to see if visually in code to understand it.

SO output I want to be something like

manchester: m&s, h&m, schuch | birmingham: game, body shop | liverpool: sports

Answer 1

You can try something like this:

public static Map<String, List<Shop>> mySortedMap(final Map<String, List<Shop>> orig)
{
    final Comparator<String> c = new Comparator<String>()
    {
        @Override
        public int compare(final String o1, final String o2)
        {
            // Compare the size of the lists. If they are the same, compare
            // the keys themsevles.
            final int sizeCompare = orig.get(o1).size() - orig.get(o2).size();
            return sizeCompare != 0 ? sizeCompare : o1.compareTo(o2);
        }
    }

    final Map<String, List<Shop>> ret = new TreeMap<String, List<Shop>>(c);
    ret.putAll(orig);
    return ret;
}

Explanation: TreeMap is the basic implementation of a SortedMap , and it can take a comparator of key values as an argument (if no comparator is passed as an argument, natural ordering of the keys prevails). Here we create an ad hoc comparator comparing the list sizes of the original map passed as an argument, and if the sizes are equal, it compares the keys themselves. Finally, we inject all elements from the origin map into it, and return it.

Answer 2

What if you try something like the following:

private static final Comparator<Map.Entry<String, List<Shop>>> CountThenAtoZ =
    new Comparator<Map.Entry<String, List<Shop>>>() {
        @Override
        public int compare(Map.Entry<String, List<Shop>> x, Map.Entry<String, List<Shop>> y) {
            // Compare shop count first. If equal, compare keys alphabetically.
            int cmp = ((Integer)x.getValue().size()).compareTo(y.getValue().size());
            return cmp != 0 ? cmp : x.getKey().compareTo(y.getKey());
        }
    };

...

public String returnAllTownsAndShopsAlphbetically() {

    List<Map.Entry<String, List<Shop>>> entries = new ArrayList<>(atlas.entrySet());
    Collections.sort(entries, CountThenAtoZ);

    String result = "";
    boolean firstTown = true;
    for (Map.Entry<String, List<Shop>> entry : entries) {
        if (!firstTown) result += " | "; else firstTown = false;
        result += entry.getKey() + ": ";

        boolean firstShop = true;
        TreeSet<Shop> sortedShops = new TreeSet<>(new ShopComparatorAtoZ());
        sortedShops.addAll(entry.getValue());
        for (Shop shop : sortedShops) {
            if (!firstShop) result += ", "; else firstShop = false;
            result += shop.getName();
        }
    }

    return result;
}

The way this works is to first create a list of the atlas entries in exactly the order we want. We need access to both the keys and their associated values to build the correct ordering, so sorting a List of Map.Entry instances is the most convenient.

We then walk the sorted list to build the resulting String , making sure to sort the shops alphabetically before adding them to the String .