[英]c++ templates, static methods and constructor
Following code crashes on(/after) the Food-destructor; 以下代码在Food-destructor上(/之后)崩溃; as shown in the stack below;
如下面的堆栈所示;
6 operator delete() 0xb7e5f4bf
5 std::string::_Rep::_M_destroy() 0xb7ec648b
4 <symbol is not available> 0xb7ec64d0
3 std::basic_string<char, std::char_traits<char>, std::allocator<char> >::~basic_string() 0xb7ec653e
2 Food::~Food() Main.cpp:126 0x0804c33c
1 main() Main.cpp:199 0x0804c288
The Food-ctor is never called but the destructor is? Food-ctor从未被调用过,而析构函数是? AFAICT things go haywire when resources of "string _text" are being freed, but I can't seem to understand why this is going wrong.
当释放“字符串_text”的资源时,AFAICT变得一团糟,但我似乎无法理解为什么这是错误的。 Obviously I could change "string _text" to "string* _text", but I'd rather understand why this goes wrong.
显然,我可以将“ string _text”更改为“ string * _text”,但是我宁愿理解为什么会出错。
class Food {
private:
string _text;
public:
Food(){
cout << "ctor Food" << endl;
}
Food(string name) {
cout << "ctor Food: name=" << name << endl;
}
virtual ~Food() {
cout << "dtor Food" << endl;
}
};
template<typename T>
class Action {
public:
static T eat(int i) {
cout << "Eat: " << i << endl;
}
};
int main() {
auto x = Action<Food>::eat(1);
}
What you are doing is undefined behavior . 您正在执行的操作是未定义的行为 。 You define a function (
eat
) as returning a type T
, but you are not actually returning anything. 您将一个函数(
eat
)定义为返回类型T
,但实际上并没有返回任何内容。 This leads to the assignment being undefined. 这导致分配未定义。
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