如何使用 PHP 解析 Soundcloud json 响应

Question

Its only getting throught the track values. What I need is to get the username. Here is what Im usign, thanks

{
        "items":[
        {
        "kind":"track",
        "id":33369455,
        "uri":"https://api.soundcloud.com/tracks/33369455",
        "user":{
        "id":758840,
        "username":"JoeDreamer",
        "avatar_url":"https://i1.sndcdn.com/avatars-000006878204-maqsrd-large.jpg?923db0b"},
        "download_count":0,
        "comment_count":1
        },
        {
        "kind":"track",
        "id":33369455,
        "uri":"https://api.soundcloud.com/tracks/33369455",
        "user":{
        "id":758840,
        "username":"JoeDreamer",
        "avatar_url":"https://i1.sndcdn.com/avatars-000006878204-maqsrd-large.jpg?923db0b"},
        "download_count":0,
        "comment_count":1
        }]
    }

$user = json_decode(file_get_contents("http://mydata.com/data.json"));
    foreach($user->items as $mydata)
    {
         echo $mydata->id . "\n";
         foreach($mydata->user as $value)
         {
              echo $value->username . "\n";
         }
    }

Answer 1

maybe

$user = json_decode(file_get_contents("http://mydata.com/data.json"));
foreach($user->items as $mydata)
{
     echo $mydata->id . "\n";
     echo $mydata->user->username;

}    

Answer 2

By adding an additional flag to the json_decode() function, we can tell the function to return an associative array instead of objects.

json_decode ( string $json [, bool $assoc = false ])

If you elect to use json_decode like this, your tasks becomes quite a lot simpler. You can access the username as if you were accessing a multidimensional array.

$user = json_decode($str,true);  // notice the "true" argument here
foreach($user['items'] as $mydata)
{
    echo $mydata['id'] . "," . $mydata['user']['username'] . "\n";
}  

Answer 3

What you might have missed is that $myData-user is an object within itself. PHP's json_decode() function works recursively passing over every element of the JSON string you use.

{
  "kind":"track",
  ...
  "user":{
    "id":758840,
    "username":"JoeDreamer",
    ...
  }
}

You'll have to access the username as a property of it's parent element. By adding the additional key variable to the inner foreach loop, we can inspect the key name and only select the username property.

...
foreach($mydata->user as $key=>$value){
  if ($key == 'username'){
    echo $value . "\n";
  }
}

The additional loop however, is redundant. Unless you have some certain specific need to loop over every one of the properties, you could simply access the username directly like this -

$mydata->user->username