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如何使用Python中的ElementTree删除xml中的节点?

[英]How do I remove a node in xml using ElementTree in Python?

I've read the remove example here and the example here is not applicable to me. 我读过remove例子在这里和例子在这里并不适用于我。

My xml file reads: 我的xml文件是:

<A>
  <B>some text</B>
  <B>other text</B>
  <B>more text</B>
</A>

What I want to do is to remove the second <B></B> from the xml. 我想要做的是从xml中删除第二个<B></B> I do not know what text it holds. 我不知道它有什么文字。 But I have the index of the <B></B> , say index = 1, which means I want to remove the second element (or node). 但我有<B></B>索引,比如index = 1,这意味着我想删除第二个元素(或节点)。

I have a code like this: 我有这样的代码:

F = open('example.xml')
self.tree = parse(F)
self.root = self.tree.getroot()
F.close()

So in this case what I want to remove is self.root[1] . 所以在这种情况下我要删除的是self.root[1]

How can this be implemented using ElementTree? 如何使用ElementTree实现?

Edit: Made my question more clear and specific. 编辑:让我的问题更清晰,更具体。

In [1]: import xml.etree.ElementTree as ET

In [2]: xmlstr=\
   ...: """
   ...: <A>
   ...:   <B>some text</B>
   ...:   <B>other text</B>
   ...:   <B>more text</B>
   ...: </A>
   ...: """

In [3]: tree=ET.fromstring(xmlstr)

In [4]: tree.remove(tree.findall('.//B')[1])

You guys are not straight to the point. 你们不是直截了当的。 I've combined my knowledge with the answers here and came out with this: 我把我的知识与答案结合在一起,并得出了这个:

for i, child in enumerate(self.root):
    if path == i:
        self.root.remove(child)
        break

where path is the index of the item I want to remove. 其中path是我要删除的项的索引。

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