违反完整性约束：1452 无法添加或更新子行：

Question

I am trying to insert values into my comments table and I am getting a error. Its saying that I can not add or update child row and I have no idea what that means.

my schema looks something like this

-- ----------------------------
-- Table structure for `comments`
-- ----------------------------
DROP TABLE IF EXISTS `comments`;
CREATE TABLE `comments` (
  `id` varchar(36) NOT NULL,
  `project_id` varchar(36) NOT NULL,
  `user_id` varchar(36) NOT NULL,
  `task_id` varchar(36) NOT NULL,
  `data_type_id` varchar(36) NOT NULL,
  `data_path` varchar(255) DEFAULT NULL,
  `message` longtext,
  `created` datetime DEFAULT NULL,
  `modified` datetime DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `fk_comments_users` (`user_id`),
  KEY `fk_comments_projects1` (`project_id`),
  KEY `fk_comments_data_types1` (`data_type_id`),
  CONSTRAINT `fk_comments_data_types1` FOREIGN KEY (`data_type_id`) REFERENCES `data_types` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
  CONSTRAINT `fk_comments_projects1` FOREIGN KEY (`project_id`) REFERENCES `projects` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
  CONSTRAINT `fk_comments_users` FOREIGN KEY (`user_id`) REFERENCES `users` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=utf32;

-- ----------------------------
-- Records of comments
-- ----------------------------

-- ----------------------------
-- Table structure for `projects`
-- ----------------------------
DROP TABLE IF EXISTS `projects`;
CREATE TABLE `projects` (
  `id` varchar(36) NOT NULL,
  `user_id` varchar(36) NOT NULL,
  `title` varchar(45) DEFAULT NULL,
  `description` longtext,
  `created` datetime DEFAULT NULL,
  `modified` datetime DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `fk_projects_users1` (`user_id`),
  CONSTRAINT `fk_projects_users1` FOREIGN KEY (`user_id`) REFERENCES `users` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=utf32;

-- ----------------------------
-- Records of projects
-- ----------------------------
INSERT INTO `projects` VALUES ('50dcbc72-3410-4596-8b71-0e80ae7aaee3', '50dcbc5c-d684-40bf-9715-0becae7aaee3', 'Brand New Project', 'This is a brand new project', '2012-12-27 15:24:02', '2012-12-27 15:24:02');

and the mysql statement I am trying to do looks something like this

INSERT INTO `anthonyl_fbpj`.`comments` (`project_id`, `user_id`, `task_id`, `data_type_id`, `message`, `modified`, `created`, `id`) 
VALUES ('50dc845a-83e4-4db3-8705-5432ae7aaee3', '50dcbc5c-d684-40bf-9715-0becae7aaee3', '1', '50d32e5c-abdc-491a-a0ef-25d84e9f49a8', 'this is a test', '2012-12-27 19:20:46', '2012-12-27 19:20:46', '50dcf3ee-8bf4-4685-aa45-4eb4ae7aaee3')

the error I get looks like this

SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails ( anthonyl_fbpj . comments , CONSTRAINT fk_comments_projects1 FOREIGN KEY ( project_id ) REFERENCES projects ( id ) ON DELETE NO ACTION ON UPDATE NO ACTION)

Answer 1

It just simply means that the value for column project_id on table comments you are inserting doesn't exist on table projects . Bear in mind that the values of column project_id on table comments is dependent on the values of ID on table Projects .

The value 50dc845a-83e4-4db3-8705-5432ae7aaee3 you are inserting for column project_id does not exist on table projects .

Answer 2

Make sure you have project_id in the fillable property of your Comment model.

I had the same issue, And this was the reason.

Answer 3

If you are adding new foreign key to an existing table and the columns are not null and not assigned default value, you will get this error,

Either you need to make it nullable or assign default value , or delete all the existing records to solve it.

Answer 4

还要确保您添加的外键与原始列的类型相同，如果您引用的列不是相同的类型，它也会失败。

Answer 5

I hope my decision will help. I had a similar error in Laravel. I added a foreign key to the wrong table.
Wrong code:

Schema::create('comments', function (Blueprint $table) {
$table->unsignedBigInteger('post_id')->index()->nullable();
...
$table->foreign('post_id')->references('id')->on('comments')->onDelete('cascade');
    });


Schema::create('posts', function (Blueprint $table) {
    $table->bigIncrements('id');
    ...
    });

Please note to the function on('comments') above. Correct code

 $table->foreign('post_id')->references('id')->on('posts')->onDelete('cascade');

Answer 6

that means that the value for column project_id on table comments you are inserting not only doesn't exist on table projects BUT also project_id probably doesn't have default value . Eg in my case I set it as NULL.

As for Laravel you can consider this expressions as a chunk of code of a migration php file, for example:

class ForeinToPhotosFromUsers extends Migration

{ /** * Run the migrations. * * @return void */

public function up()
{
    Schema::table('users', function (Blueprint $table) {
    $table->unsignedBigInteger('photo_id')->nullable();// ! ! ! THIS STRING ! ! !
    $table->foreign('photo_id')->references('id')->on('photos');
});
}

}

Obviously you had to create the Model class(in my case it was Photo) next to all these.

Answer 7

First delete the constraint "fk_comments_projects1" and also its index. After that recreate it.

Answer 8

Maybe you have some rows in the table that you want to create de FK.

Run the migration with foreign_key_checks OFF Insert only those records that have corresponding id field in contents table.

Answer 9

You also get this error if you do not create and populate your tables in the right order. For example, according to your schema, Comments table needs user_id , project_id , task_id and data_type_id . This means that Users table, Projects table, Task table and Data_Type table must already have exited and have values in them before you can reference their ids or any other column.

In Laravel this would mean calling your database seeders in the right order:

class DatabaseSeeder extends Seeder
{
    /**
     * Seed the application's database.
     *
     * @return void
     */
    public function run()
    {
        $this->call(UserSeeder::class);
        $this->call(ProjectSeeder::class);
        $this->call(TaskSeeder::class);
        $this->call(DataTypeSeeder::class);
        $this->call(CommentSeeder::class);
    }
}

This was how I solved a similar issue.

Answer 10

In case someone is using Laravel and is getting this problem. I was getting this as well and the issue was in the order in which I was inserting the ids (ie, the foreign keys) in the pivot table.

To be concrete, find below an example for a many to many relationship:

wordtokens <-> wordtoken_wordchunk <-> wordchunks

// wordtoken_wordchunk table
Schema::create('wordtoken_wordchunk', function(Blueprint $table) {
        $table->integer('wordtoken_id')->unsigned();
        $table->integer('wordchunk_id')->unsigned();

        $table->foreign('wordtoken_id')->references('id')->on('word_tokens')->onDelete('cascade');
        $table->foreign('wordchunk_id')->references('id')->on('wordchunks')->onDelete('cascade');

        $table->primary(['wordtoken_id', 'wordchunk_id']);
    });

// wordchunks table
Schema::create('wordchunks', function (Blueprint $table) {
        $table->increments('id');
        $table->timestamps();
        $table->string('text');
    });

// wordtokens table
Schema::create('word_tokens', function (Blueprint $table) {
        $table->increments('id');
        $table->string('text');
});

Now my models look like follows:

class WordToken extends Model
{
   public function wordchunks() {
      return $this->belongsToMany('App\Wordchunk');
   }
}

class Wordchunk extends Model
{

    public function wordTokens() {
        return $this->belongsToMany('App\WordToken', 'wordtoken_wordchunk', 'wordchunk_id', 'wordtoken_id');
    }
}

I fixed the problem by exchanging the order of 'wordchunk_id' and 'wordtoken_id' in the Wordchunk model.

For code completion, this is how I persist the models:

private function persistChunks($chunks) {
    foreach ($chunks as $chunk) {
        $model = new Wordchunk();
        $model->text = implode(' ', array_map(function($token) {return $token->text;}, $chunk));
        $tokenIds = array_map(function($token) {return $token->id;}, $chunk);
        $model->save();
        $model->wordTokens()->attach($tokenIds);
    }
}

Answer 11

I had this issue when I was accidentally using the WRONG "uuid" in my child record. When that happens the constraint looks from the child to the parent record to ensure that the link is correct. I was generating it manually, when I had already rigged my Model to do it automatically. So my fix was:

$parent = Parent:create($recData); // asssigning autogenerated uuid into $parent

Then when I called my child class to insert children, I passed this var value:

$parent->uuid

Hope that helps.

Answer 12

I had the same error, the problem was that I was trying to add role_id foreign to the users table, but role_id did not have a default value, so the DB did not allow me to insert the column because I already had some users and it didn't know how to add the column to them. Since I was in development I just used migrate:fresh , but if I was on production, I would probably set a default value to the role_id and not make it not constrained until I had the corresponding role on the DB.

Answer 13

可能是您插入的外键值与主键的值不匹配。

Answer 14

问题可能是因为在您尝试添加的具有 project_id 的数据库中找不到项目记录...

Answer 15

I had a table fulfilled with some entries that has dead foreigners keys. once i cleaned the table, i was able to add a new constraint.

DELETE FROM `table_with_bad_entries` WHERE `expected_foreign_key` not in (select `id` from `the_referenced_table`);

Answer 16

就我而言，它不起作用，因为我在模型中的其中一个名称中留了一个空格，请在此处输入图像描述

Answer 17

I just exported the table deleted and then imported it again and it worked for me. This was because i deleted the parent table(users) and then recreated it and child table(likes) has the foreign key to parent table(users).