c-将内存分配给指向函数的指针数组

Question

I want my function to create an array and allocate memory for n pointers to functions (for example, functions that have no parameters and return int) and to return a pointer to that array.

I tried doing:

void* f(int n){
   return calloc(int (*arrayName[])(void),n);
}

But i'm getting a syntax error. I'm pretty new to c and i tried to dig for an hour how to solve this issue with no success. using the man page i figured calloc is the way to go but i might be wrong.

Answer 1

Make your life easier and use typedef s:

typedef int (*fp)();

fp * f(size_t n)
{
    return calloc(n, sizeof(fp));
}

_{The hand-rolled declaration: int (*f(size_t n))()}

Answer 2

或者，如果您不想使用typedef（提示：出于完整性考虑，您仍然想要typedef ）：将类型包装在sizeof() ：

return calloc(n, sizeof(int (*)(void)));