将Web应用程序部署到Apache Tomcat的最简单方法

Question

I'm trying to deploy my first servlet to my server. There are, of course, many tutorials online. But most of them are very detailed and complicated, and I only need to deploy a few simply servlets to this server.

I found what I think to be the shortest method of deployment: Deployment on Tomcat Startup . I moved my .WAR file ( FirstProject.war ) into $CATALINA_BASE/webapps folder, but when trying to access it ( ServerIP/FirstProject ) I get the " The requested resource is not available ." error.

Is there anything I forgot in the process of deployment?

I know that deployOnStartup has to be set to true , but I didn't change anything with the server's hosts, so the current host is localhost . I didn't change its settings, so deployOnStartup should be true (It's said that true is the default).

What am I missing?

Answer 1

You are using easiest way but I don't know what you are missing. Here what I would suggest is run your server and access through localhost:8080 then click manage app then enter username and password then you can deploy your war. If you have any query post command.

Answer 2

Even i used to face this problem while deploying my first web application on Jboss and Apache ..

Even though your code is working properly with all your servlet mappings and paths using in your content files ...some times they kick back in real time environment ..So we have to know the proper deployment folder structure and accordingly we have to change our paths in the code

what i am concluding is check the below lines of code

   Examples, assuming root is http://foo.com/site/

Absolute path, no matter where we are on the site

/foo.html

will refer to http://foo.com/site/foo.html

Relative path, assuming the containing link is located in http://foo.com/site/part1/bar.html

../part2/quux.html

will refer to http://foo.com/site/part2/quux.html

or

part2/blue.html

will refer to http://foo.com/site/part1/part2/blue.html