[英]How to display posts of a particular category in php?
The problem here is , when i type cat='hotels' manually , it displays the detail of that category . 这里的问题是,当我手动输入cat ='hotels'时,它会显示该类别的详细信息。
But when i give cat=$category , (category will be selected by user) , it says that category is undefined variable . 但是当我给cat = $ category时,(类别将由用户选择),它说类别是undefined variable。
What i want is , when i click on any category , the posts related to that category should get displayed . 我想要的是,当我单击任何类别时,应该显示与该类别相关的帖子。
Do help to solve this . 帮忙解决这个问题。
Below is the code . 下面是代码。
Here's the script . 这是脚本。
<script>
$(document).ready(function(){
$(".button").click(function(){
$("#display").load("cat.php");
});
});
</script>
Here's my html. 这是我的HTML。
<ul>
<li class="button"><a href="#">Hotels</a></li>
<li class="button"><a href="#">Resorts</a></li>
<li class="button"><a href="#">Hills</a></li>
</ul>
<div id="display"></div>
This is my insert.php file. 这是我的insert.php文件。
$id = isset($_POST['post_id'])?$_POST['post_id']:'';
$category=$_POST['cat'];
mysql_connect('localhost','root','');
mysql_select_db("database") or die("Unable to select database");
$insertquery="INSERT INTO posts VALUES('$id','$category')";
$result=mysql_query($insertquery);
if(! $result )
{
die('Could not enter data: ' . mysql_error());
}
else {
echo "Entered data successfully\n";
header('Location:home.php');
}
mysql_close();
?>
This is the code (cat.php) to display it on my home page. 这是将代码显示在我的主页上的代码(cat.php)。
<?php
$row="";
$link = mysql_connect("localhost","root","");
mysql_select_db("database");
$query = "SELECT * FROM posts WHERE cat=$category";
$result = mysql_query($query) or die("Query to get data failed with error: ".mysql_error());
while($row = mysql_fetch_array($result)) {
echo $row['cat'];
}
mysql_close($link);
?>
Change 更改
$query = "SELECT * FROM posts WHERE cat=$category";
To 至
$query = "SELECT * FROM posts WHERE cat='$category'";
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