[英]For some reason my if statement isn't triggering
I have created an onSharedPreferencesChangeListener which is working correctly. 我创建了一个正常工作的onSharedPreferencesChangeListener。 I know this because when I setup the listener I logged the listener and it is triggering on a change.
我知道这一点,因为当我设置监听器时,我记录了监听器并且它正在触发更改。
However, I was getting an error when I was trying to switch the key variable (saying that I need JRE 1.7+ in order to switch a string), so I changed it to if-elseif statements. 但是,当我尝试切换密钥变量时(我说我需要JRE 1.7+才能切换字符串)时出现错误,因此我将其更改为if-elseif语句。
The if-elseif statements weren't triggering so I changed the first two to if statements and put the elseif after that (thinking that the elseif might have been the problem). if-elseif语句没有触发,所以我将前两个更改为if语句并在之后放入elseif(认为elseif可能是问题)。 Still no triggering.
仍然没有触发。
The weird thing is that when I logged the event trigger, I output " "+key+" " as the string and the key value is the exact strings that I'm testing for. 奇怪的是,当我记录事件触发器时,我输出“ ”+ key +“ ”作为字符串,键值是我正在测试的确切字符串。
Here is my code, can someone point me in the right direction please? 这是我的代码,有人能指出我正确的方向吗?
// logic for action when a shared preference is changed.
prefs.registerOnSharedPreferenceChangeListener( new SharedPreferences.OnSharedPreferenceChangeListener() {
@Override
public void onSharedPreferenceChanged(SharedPreferences sharedPreferences, String key) {
String TAG = "UltimateScoreboard";
if (key == "Main_Clock_Minutes") {
msMainClockStart = Long.valueOf( prefs.getString( "Main_Clock_Minutes", "0" ) ) * 60000;
Log.i( TAG, key + " changed: " + String.valueOf(msMainClockStart) );
}
if ( key == "Use_ShotClock" ) {
useShotClock = prefs.getBoolean( "Use_ShotClock", false );
if( useShotClock )
btnShotClock.setVisibility( View.VISIBLE );
else
btnShotClock.setVisibility( View.INVISIBLE );
Log.i( TAG, key );
}
else if ( key == "Shot_Clock_Seconds" ) {
msShotClockStart = Long.valueOf( prefs.getString( "Shot_Clock_Seconds", "0" ) ) * 1000;
Log.i( TAG, key + " changed: " + Long.valueOf(msShotClockStart) );
}
You must use the String.equals()
function to compare strings. 您必须使用
String.equals()
函数来比较字符串。 ==
with Strings only compares memory locations. ==
with Strings仅比较内存位置。
For example: if (key.equals("Main_Clock_Minutes"))
例如:
if (key.equals("Main_Clock_Minutes"))
You can not compare strings using == . 您无法使用==比较字符串。 Use the String class methods
equals()
or equalsIgnoreCase()
. 使用String类方法
equals()
或equalsIgnoreCase()
。
if ( key.equals("Use_ShotClock") ) { }
This is how you compare strings 这是比较字符串的方式
you should compare like if ( key.equals("Use_ShotClock")) or if ( key.equalsIgnoreCase("Use_ShotClock")). 你应该比较if(key.equals(“Use_ShotClock”))或if(key.equalsIgnoreCase(“Use_ShotClock”))。 because string are objects in java.
因为string是java中的对象。 so if you compare like if ( key == "Use_ShotClock" ) it will try to compare the referances of those 2 string objects which will be different.
因此,如果您比较if(key ==“Use_ShotClock”),它将尝试比较那两个不同的字符串对象的参考。
Have you tried using .equals()
in comparing strings
? 您是否尝试过使用
.equals()
来比较strings
?
Like this: 像这样:
if (key.equals("Main_Clock_Minutes")) {
msMainClockStart = Long.valueOf( prefs.getString( "Main_Clock_Minutes", "0" ) ) * 60000;
Log.i( TAG, key + " changed: " + String.valueOf(msMainClockStart) );
} else if ( key.equals("Use_ShotClock")) {
useShotClock = prefs.getBoolean( "Use_ShotClock", false );
if( useShotClock )
btnShotClock.setVisibility( View.VISIBLE );
else
btnShotClock.setVisibility( View.INVISIBLE );
Log.i( TAG, key );
} else if ( key.equals("Shot_Clock_Seconds")) {
msShotClockStart = Long.valueOf( prefs.getString( "Shot_Clock_Seconds", "0" ) ) * 1000;
Log.i( TAG, key + " changed: " + Long.valueOf(msShotClockStart) );
}
Strings have to be tested on equality with String's method equals(String s). 必须使用String的方法equals(String s)对字符串进行相等性测试。
The "==" Operator hasn't been overloaded for Strings and because a String is a reference Type (it's an object, not a primitive type) it's the memory address which is compared using "==". “==”运算符没有为Strings重载,因为String是引用类型(它是一个对象,而不是一个基本类型),它是使用“==”进行比较的内存地址。 Because of Javas ability to share memory for multiple variables, there is a chance to get true when comparing strings with "==", but that's less probable and very unpredictable.
由于Javas能够为多个变量共享内存,因此在将字符串与“==”进行比较时,有可能实现,但这种可能性较小且非常不可预测。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.