扩展的glob无法按预期扩展

Question

I have a bash script named except.sh which is passed a list of files/directories like so:

$ ls
a b c d/
$ ./except.sh b c

When calling except this way, it should expand to ad/ ie all files/directories except the given names.

Here's how I tried to implement this:

#!/usr/bin/env bash

# enable extended globbing
shopt -s extglob

# set IFS to | so that $* expands correctly
IFS='|'

printf '%s' !("$*")

Given bc as parameters, the last line should expand to

printf '%s' !(b|c)

resulting in ad being printed. But to my suprise,

abcd

is printed. What am I doing wrong?

Answer 1

The problem is due to the IFS variable override (after you override this variable, bash pattern matching behaves odd, example, try ls -d !(b|c) before and after setting IFS ), the following should work:

#!/usr/bin/env bash

# enable extended globbing
shopt -s extglob

PARAMS=$(tr ' ' '|' <<< $*)
printf '%s' !($PARAMS)

Answer 2

The problem is that $* is in double quotes, which means that its contents will not be treated as a pattern, just like echo "*" does not expand the asterisk. Combining the outer pattern with the inner quoted portion automatically escapes the latter, so !("b|c") is treated like !(b\\|c) . Negation of the nonexistent b|c file naturally expands to all files in the directory.

An additional problem is that extended globbing is messed up by IFS being set to | , so you must reset it before expanding the pattern. Therefore, you must do the expansion in two steps: first, calculate the pattern, then reset IFS and expand it:

#!/usr/bin/env bash

# enable extended globbing
shopt -s extglob

# temporarily set IFS to | so that $* expands to part an extended pattern
old_ifs=$IFS
IFS='|'
pattern="!($*)"
IFS=$old_ifs

printf '%s' $pattern