[英]retrieving value of an enumerated type in Z3Py
How do I retrieve the values of an enumerated variable v
? 如何检索枚举变量v
的值? For example, 例如,
vTyp, (val1,val2,val3) = EnumSort('vTyp',['val1','val2','val3'])
v = Const('my variable',vTyp)
Now, given just the above variable v
, how would I retrieve a list of values [val1,val2,val3]
of v
(where val1,val3,val3
are expressions as above) ? 现在, 只给定上述变量v
,我将如何检索值的列表[val1,val2,val3]
的v
(其中val1,val3,val3
是表达如上)?
I have tried [v.sort().constructor(0), ...(1), ...(2)]
but the constructor method does not return an expression. 我试过[v.sort().constructor(0), ...(1), ...(2)]
但是构造函数方法没有返回表达式。
The expression v.sort().constructor(0)
returns a Z3 function declaration. 表达式v.sort().constructor(0)
返回Z3函数声明。 In Z3, constants are functions with 0 arguments. 在Z3中,常量是具有0个参数的函数。 To convert the declaration in a constant expression, we should use v.sort().constructor(0)()
. 要在常量表达式中转换声明,我们应该使用v.sort().constructor(0)()
。
BTW, the function is_func_decl
can be used to test whether an object is a Z3 function declaration or not. 顺便说一句,函数is_func_decl
可用于测试对象是否是Z3函数声明。 The function is_expr
is the equivalent for Z3 expressions. 函数is_expr
与Z3表达式等效。
print is_func_decl(v.sort().constructor(0))
print is_expr(v.sort().constructor(0))
print is_expr(v.sort().constructor(0)())
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