[英]How to get two (0~15) numbers as properties with one byte as backing field?
I'm making a tile based 2d platformer and every byte of memory is precious. 我正在制作基于图块的2d平台程序,并且每个字节的内存都很宝贵。 I have one byte field that can hold values from 0 to 255, but what I need is two properties with values 0~15. 我有一个字节字段,可以保存从0到255的值,但是我需要两个值为0〜15的属性。 How can I turn one byte field into two properties like that? 我如何将一个字节字段变成这样的两个属性?
do you mean just use the lower 4 bits for one value and the upper 4 bits for the other? 您的意思是只将低4位用于一个值,将高4位用于另一个值?
to get two values from 1 byte use... 从1个字节中获取两个值,使用...
a = byte & 15;
b = byte / 16;
setting is just the reverse as 设置只是相反
byte = a | b * 16;
Using the shift operator is better but the compiler optimizers usually do this for you nowadays. 使用shift运算符会更好,但是如今,编译器优化器通常会为您执行此操作。
byte = a | (b << 4);
To piggy back off of sradforth's answer, and to answer your question about properties: 摆脱sradforth的回答,并回答有关属性的问题:
private byte _myByte;
public byte LowerHalf
{
get
{
return (byte)(_myByte & 15);
}
set
{
_myByte = (byte)(value | UpperHalf * 16);
}
}
public byte UpperHalf
{
get
{
return (byte)(_myByte / 16);
}
set
{
_myByte = (byte)(LowerHalf | value * 16);
}
}
Below are some properties and some backing store, I've tried to write them in a way that makes the logic easy to follow. 以下是一些属性和一些后备存储,我试图以一种易于理解的方式编写它们。
private byte HiAndLo = 0;
private const byte LoMask = 15; // 00001111
private const byte HiMask = 240; // 11110000
public byte Lo
{
get
{
// ----&&&&
return (byte)(this.hiAndLo & LoMask);
}
set
{
if (value > LoMask) //
{
// Values over 15 are too high.
throw new OverflowException();
}
// &&&&0000
// 0000----
// ||||||||
this.hiAndLo = (byte)((this.hiAndLo & HiMask) | value);
}
}
public byte Hi
{
get
{
// &&&&XXXX >> 0000&&&&
return (byte)((this.hiAndLo & HiMask) >> 4);
}
set
{
if (value > LoMask)
{
// Values over 15 are too high.
throw new OverflowException();
}
// -------- << ----0000
// XXXX&&&&
// ||||||||
this.hiAndLo = (byte)((hiAndLo & LoMask) | (value << 4 ));
}
}
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