如何从ajax过滤返回数据的正文html？
[英]How do I filter body html the returned data from ajax?
问题描述
My purpose is, I want to take specific html out from data and update that area only. 
我的目的是，我想从数据中取出特定的html并仅更新该区域。
How do I filter the returned data from jQuery.ajax? 如何从jQuery.ajax过滤返回的数据？
This link is a old post but I do have the exactly same problem. 这个链接是一个老帖子，但我确实有完全相同的问题。
The solution giving from the link is $("[ref=B]").html(data).find( '[ref=A]' ); 从链接给出的解决方案是$("[ref=B]").html(data).find( '[ref=A]' );
However, if I do so, the entire page will write on <span ref='B'> first then find the selector inside of it..... 但是，如果我这样做，整个页面将首先在<span ref='B'>上写，然后找到它内部的选择器.....
The alternative way to only find '[ref=A]' is 找到'[ref = A]'的替代方法是
html = $(data).filter('[ref=B]').find('[ref=A]').html() // this way will work
none of these will work 这些都不会奏效
$(data).find('[ref=A]').html();
$(data).filter('[ref=A]').html();
$(data).filter('body').html();
$(data).find('body').html();
HTML HTML
`<body>
<span ref='B'><span ref='A'>abc</span></span>
</body>`
JS JS
$(function() {
$.get(window.location.pathname + window.location.search, function(data){ alert(data);});
});
Returned Data 返回的数据
<html>
<body>
<span ref='B'><span ref='A'>abc</span></span>
</body>
</html>
My question is, is there a solution to filter body`s html from data which returned from $.ajax?? 我的问题是，是否有一个解决方案来从$ .ajax返回的数据中过滤body的html？ like 喜欢
body_html = $(data).???????
then I can do whatever I want, like 然后我可以做任何我想做的事，比如
body_html.find('xxxx');
Thank you very much for your advice. 非常感谢您的建议。
2 个解决方案
解决方案1
3 已采纳 2013-01-08 00:38:41
You can use a DocumentFragment to simulate your html and do your search without appending it to the DOM . 您可以使用DocumentFragment来模拟您的html并进行搜索，而无需将其附加到DOM 。
// Create your DocumentFragment to be able to work without DOM
var body_html = document.createDocumentFragment();
// Convert and append data from your jQuery to work with fragment
body_html.appendChild($(data)[0]);
// Now you can select using your jQuery
var $body_html = $(body_html);
// Now you can use the find or whatever you want, like if it was in the DOM
$body_html.find('.foo');
// Or you can append in your current document,
// but attention, after it the fragment reference is erased
$body_html.appendTo(document.body);
// now you need to get reference again from body,
// because your fragment doesn't exists anymore.
// So... if you try:
console.log(body_html); // undefined
console.log($body_html); // jquery over undefined, probably just a jquery useless
// At this point you will need to reference from DOM to continue manipulation
$body_html = $(document.body);
// Now I'm ready to continue the work
// This var is like your DocumentFragment, but already on DOM.
You also can do a filter in jQuery templating $(data).filter('.foo') but as you can see in this tests , your performance will drop a lot. 你也可以在jQuery模板化$(data).filter('.foo')进行过滤，但正如你在本次测试中看到的那样，你的表现会下降很多。
解决方案2
2 2013-01-08 01:01:07
$("[ref=B]").append($(data).find("[ref=A]"));
The way you do it in your question, the last part find( '[ref=A]' ) is useless. 你在问题中的方式，最后一部分find( '[ref=A]' )是没用的。
[Edit] Also, the other question is more than 2 years old. [编辑]另外，另一个问题是超过2年。 For recent versions of jQuery you might need additional quotes: 对于最新版本的jQuery，您可能需要其他引号：
$("[ref='B']").append($(data).find("[ref='A']"));
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