[英]python: elegant and code saving way to convert a list
First of all sorry for the easy question. 首先,对这个简单的问题感到抱歉。 I have a list (just an example)
我有一个清单(只是一个例子)
points = [[663963.7405329756, 6178165.692240637],
[664101.4213951868, 6177971.251818423],
[664099.7474887948, 6177963.323432223],
[664041.432877932, 6177903.295650704],
[664031.8017317944, 6177895.797176996],
[663963.7405329756, 6178165.692240637]]
I need to convert it to the following form 我需要将其转换为以下形式
points = [(663963.7405329756, 6178165.692240637),
(664101.4213951868, 6177971.251818423),
(664099.7474887948, 6177963.323432223),
(664041.432877932, 6177903.295650704),
(664031.8017317944, 6177895.797176996),
(663963.7405329756, 6178165.692240637)]
in order to create a Polygon
object using shapely module . 为了使用shapely模块创建一个
Polygon
对象。 I wrote several loops but really not elegant and time consuming. 我编写了几个循环,但实际上并不优雅且耗时。 Do you know the best way to convert the first list into the second?
您知道将第一个列表转换为第二个列表的最佳方法吗?
Thanks 谢谢
converted = map(tuple, points) # Python 2
converted = list(map(tuple, points)) # or BlackBear's answer for Python 3
converted = [tuple(x) for x in points] # another variation of the same
converted = [(a,b) for a,b in points]
converted = [tuple(l) for l in points]
与@BlackBear提供的解决方案相比,此方法适用于任意大小的子列表。
points = [tuple(x) for x in points]
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