使用运行时确定的类型参数构建通用对象

Question

i Have the folowing Code and i call this by the function, buy i need to call it fom a Type otherType dynamic at runtime.

// this in code this works fine
DooClass newOne = GetInstance<DooClass>();

// The function
private T GetInstance<T>() where T : new()
{
    T item = SomeClass.Instance.GetItem<T>();
    if (item == null)
    {
       item = new T();
    }
    return item;
}

All the objects Have the same Parent ParentClass

//This is what i want to do or something like this
public void SomeFunction(Type someType)
{
   ParentClass newObj = GetInstance<someType>();
}

/////Solved using comment below by this

private ParentClass GetElement(Type theType)
{
   ParentClass item = (ParentClass)SomeClass.Instance.GetItem(theType);
   if (item == null)
   {
      item = (ParentClass)Activator.CreateInstance(theType);
   }
   return item;
}

and the metod in the class SomeClass.Instance.GetItem(); to dont use generic type use object all and now the Type is pased as parameter

Answer 1

Try Activator.CreateInstance

  ParentClass newObj = (ParentClass)Activator.CreateInstance(type)

From MSDN

Activator.CreateInstance -> Creates an instance of the specified type using that type's default constructor.