[英]Char to QString
I have a char array and want to convert one of the values from char to qstring:我有一个 char 数组,想将其中一个值从 char 转换为 qstring:
unsigned char inBuffer[64];
....
QString str= QString(*inBuffer[1]);
ui->counter->setText(str);
This isn't working (I get a compiler error).这不起作用(我收到编译器错误)。 Any suggestions?有什么建议么?
Please check http://qt-project.org/doc/qt-4.8/qstring.html请检查http://qt-project.org/doc/qt-4.8/qstring.html
QString & operator+= ( char ch )
QString & operator= ( char ch )
You can use operator+= to append a char, or operator= to assign a char.您可以使用 operator+= 附加一个字符,或使用 operator= 分配一个字符。
But in your code it will call constructor, not operator=.但是在您的代码中,它将调用构造函数,而不是 operator=。 There is no constructor for char, so your code can not compile. char 没有构造函数,因此您的代码无法编译。
QString str;
str = inBuffer[1];
QString has a constructor QString 有一个构造函数
QString ( QChar ch )
So u can use following code to do that所以你可以使用以下代码来做到这一点
QString str= QChar(inBuffer[1]);
or要么
QString str(QChar(inBuffer[1]));
if ur var is: char * p = "hi there";
如果你的 var 是: char * p = "hi there";
You just QString myGreet = QString::fromLocal8Bit(p);
你只是QString myGreet = QString::fromLocal8Bit(p);
How did you declare inBuffer ?你是如何声明inBuffer 的? If you meant outBuffer , drop the dereference operator:如果您的意思是outBuffer ,请删除取消引用运算符:
QString str = outBuffer[1];
This is the easiest way to do that:这是最简单的方法:
QString x="";
QChar y='a';
x+=y;
So here you have a QString with the char.所以这里你有一个带有字符的 QString 。
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