使用CodeBehind动态生成的HTML打开弹出窗口

Question

At a certain point i have a dynamicly generated string with html in my code-behind.
I want to open a popup with has that html as its source.

I have tried the following:
I created this method on my .aspx site (Javascript):

    function OpenWindowWithHtml(html, title) {
            var myWindow = window.open('', title);
            myWindow.document.write(html);
            myWindow.focus();
     }  

And in the code-behind i have this:

    Response.Write("OpenPopupWithHtml(\"" + html + "\", \"" + title + "\");");  

But when i try to execute this i get an error.
Does anybody see, what i do wrong here?
Or does somebody know a better way to do this?

Answer 1

EDIT

on button click it shoudl be like this

protected void btnAbct_Click(object sender, EventArgs e) {
   ClientScript.RegisterClientScriptBlock(this.GetType(), "Alert", "OpenPopupWithHtml('" + html + "', '" + title + "');");
}

---

To execute the code ie. function you written in javascript

 ClientScript.RegisterStartupScript(this.GetType(),
   "newWindow", "OpenPopupWithHtml('" + html + "', '" + title + "');");

---

you can register client script like this

if (!ClientScript.IsClientScriptBlockRegistered("exampleScript"))
    ClientScript.RegisterStartupScript(this.GetType(), "exampleScript","
<script language = "'javascript'">
alert('you just registered the start up script')
</script>
");

from the code behind file of asp.net

To Open pop-Up window , just replace this line in above code

 ClientScript.RegisterStartupScript(this.GetType(),
   "newWindow", String.Format("<script>window.open('{0}');</script>",
         "mypage.html"));

Check this for detail : Register Client script in ASP.NET