django / python如何通过发布json连接到Web服务

Question

I am developing an application that connects to a web service, providing a json string with data and receiving a reply. I use the following code, where I build the json and try to post it:

def connectToService(request):
    data='foxp3 factor'
    l=[] 
    l.append(data)
    l.append(80)
    l.append(5)
    data=json.dumps({"findCitations":l})
    result = urllib2.urlopen('http://www.example.com/webservice', urllib.urlencode(data))

But it doesn't work. I hope that the json reply from the web service will be stored in result and then I will figure out a way to parse it, probably by deseriazizing it. Although there is much literature about it (json, simplejson, HttpPequest) and it has to be pretty simple I have not manage to do it yet. Any solutions?

Answer 1

Why not you are using the requests library

Like

payload = {'key1': 'value1', 'key2': 'value2'}
>>> r = requests.post("http://www.example.com/webservice", data=payload)
>>> print r.text

Where payload is the parameter that you are passing .

Hope this will give you an idea

Answer 2

You can use this code and some error handling idea:

    payload = {'key1': 'value1', 'key2': 'value2'}
    url = "http://www.example.com/webservice"

    try:
        response = requests.post(url, data=payload)

    except requests.exceptions.ConnectionError:
        message = 'This is not the domain we are looking for. URL is: %s' % url
        print e
        sys.exit(1)

    except requests.exceptions.ConnectTimeout:
        message = 'Too slow connection! URL is: %s' % url
        print e
        sys.exit(1)

    except Exception as e:
        message = 'Unknown Error: %(message)s URL is: %(url)s' % {'message': str(e), 'url': url}
        print e
        sys.exit(1)

    else:
        return response.json()