查询以返回（分组的）行，其中不存在具有column = condition的行

Question

Let's say I have a table with two columns, a client_id and a boolean.

There are multiple data entries for a given client_id, each of which may or may not have the boolean value set to true.

I need a query that will return only the client_ids that have NO ROWS with the boolean set to true, and I need it grouped by client_id.

I'm sure this is simple, it just escapes me right now.

Answer 1

Use the HAVING clause to filter the groups:

SELECT client_id FROM my_table GROUP BY client_id HAVING SUM(boolean) = 0

Note that SUM(boolean) works in MySQL because it does not have true boolean types; in other RDBMS you would either have to use a different aggregate function or else test the boolean and return a result that can be used in SUM() :

... HAVING SUM(CASE WHEN boolean THEN 1 END) = 0