如何在php中从一个数据库表显示数据到另一数据库表的视图页？

Question

I have 2 db tables aspect & aspectdet_1. Each have Add, View, Edit & Delete pages.

Table: aspect has rows ascode & asname .

Table: aspectdet_1 has rows Dept_Code , ascode , astype , cndtn & asscope .

I want to display asname from Table: aspect in Table: aspectdet_1 's view page. I used the code

$query="SELECT aspectdet_1.Dept_Code, aspectdet_1.ascode, aspectdet_1.astype, aspectdet_1.cndtn, aspectdet_1.asscope, aspect.asname ".
    "FROM aspectdet_1, aspect ".
    "WHERE aspectdet_1.ascode = aspect.ascode ";

It works in view page.

But when I want to edit or delete that pages not supporting.

Is that code right?

What to do for edit & delete?

Answer 1

Sounds like database privilege problem. Please make sure whether mysql-user you used to connect to the databases (used in mysql_connet) has edit and delete privileges for the tables.

You can check the database table privileges in your Phpmyadmin

A nice tutorial about privileges: http://dev.mysql.com/doc/refman/5.1/en/privileges-provided.html