[英]How to call a shell script and pass argument from another shell script
I'm calling a shell script from another shell script and the called script requires some input (command line) parameters. 我从另一个shell脚本调用shell脚本,并且被调用的脚本需要一些输入(命令行)参数。
I'm have below mentioned code, but thats not working. 我有下面提到的代码,但那不起作用。 I don't know why the argument values are not passed to the called script.
我不知道为什么参数值没有传递给被调用的脚本。
script1.sh
=======================================
#!/bin/bash
ARG1="val1"
ARG2="val2"
ARG3="val3"
. /home/admin/script2.sh "$ARG1" "$ARG2" "$ARG3"
script2.sh
=======================================
#!/bin/bash
echo "arg1 value is: $1 ....."
echo "arg2 value is: $2 ....."
echo "arg3 value is: $3 ....."
But when I execute script1.sh I get following result: 但是当我执行script1.sh时,我得到以下结果:
arg1 value is: .....
arg2 value is: .....
arg3 value is: .....
What am I missing? 我错过了什么?
By sourcing the second script with . /home/admin/script2.sh
通过采购第二个脚本
. /home/admin/script2.sh
. /home/admin/script2.sh
, you're effectively including it in the first script, so you get the command line arguments to the original script in $@
. . /home/admin/script2.sh
,你有效地将它包含在第一个脚本中,所以你得到$@
原始脚本的命令行参数。 If you really want to call the other script with arguments, then do 如果你真的想用参数调用另一个脚本,那么就做
/home/admin/script2.sh "$ARG1" "$ARG2" "$ARG3"
(make sure it's executable). (确保它是可执行的)。
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