将参数从主窗口传递到弹出的Qdialog窗口

Question

I have Qdialog with that I open from main window:

Dialog = myDialog(self)

Here is the code from new opened Dialog:

class myDialog(QtGui.QDialog, Ui_DialogCalibration):
def __init__(self, parent=None):
    super(myDialog, self).__init__(parent)
    self.setupUi(self)

How can pass parameter(lint) from main window to this new window, something like

Dialog = myDialog(self, listInformation)

and then in myDialog class use that list

Answer 1

class myDialog(QtGui.QDialog, Ui_DialogCalibration):
    def __init__(self, parent=None, listInfo):
        super(myDialog, self).__init__(parent)
        self.listInfo = listInfo
        self.setupUi(self)

Then, when you go to create the myDialog , you can add the list as a parameter. When you need to use it inside of your myDialog , you would access it as self.listInfo .

EDIT: To further expand on the comments:

If you have def __init__(self, parent=None, listInfo=None) , you would call it as Dialog = myDialog(parent=self, listInfo=listInfo) . If you had it as def __init__(self, parent, listInfo) you would do Dialog = myDialog(self, listInfo) . Hopefully you see the pattern here.