在Excel中使用OR函数时出错

Question

I am using Excel Formula OR in an Excel formula and am little surprised the way it is behaving.

I am using the following Excel formula :

=IF(OR(ISERROR(funct(A1:A5)), funct(A1,A5)=0), "ERROR", funct(A1,A5))

My understanding was that, if ISERROR(funct(A1:A5)) True(or False) , the result of OR operation would be True(or False).

In my experiment, I was expecting the answer to be "ERROR" as the ISERROR(funct(A1:A5)) results in true .

But I am getting #VALUE! error. Any Idea what could be wrong. Or if I can rephrase the formula to make it work.

Thanks

Answer 1

=IF(ISERROR(funct(A1:A5)),"ERROR",IF(funct(A1:A5)=0,"ERROR",funct(A1:A5)))

Answer 2

I recommend Tim's answer but if func() is a large function, as you say, then you might want to minimise the number of times it's used. I'm assuming that the same function should be invoked throughout the formula, ie func(A1:A5)

In Excel 2007 or later you could use IFERROR function:

=IFERROR(IF(func(A1:A5)=0,"ERROR",func(A1:A5)),"ERROR")

or in earlier versions you could force func(A1:A5) to give an error when equal to zero by dividing 1 by func(A1:A5):

=IF(ISERROR(1/func(A1:A5)),"ERROR",func(A1:A5))

Edit: Taking that one step further you could combine both of those approaches in Excel 2007 or later so that you only need to call func once:

=IFERROR(1/(1/func(A1:A5)),"ERROR")

Answer 3

I think you're missing a close bracket.

Try this:

=IF(OR(ISERROR(funct(A1:A5)), func(A1,A5)=0), "ERROR", func(A1,A5))

Answer 4

=IF(OR(ISERROR(funct(A1:A5)), funct(A1,A5)=0), "ERROR", func(A1,A5)) - close look at your formula resulted in the suggestion: funct(A1,A5)=0 and func(A1,A5) are really different functions, or this is a typo in your formula? Perhaps that's the case.