Java中的javascript逗号运算符

Question

I'm trying to convert the following javascript to java

var lat2 = Math.asin( Math.sin(lat1)*Math.cos(d/R) + 
          Math.cos(lat1)*Math.sin(d/R)*Math.cos(brng) );
var lon2 = lon1 + Math.atan2(Math.sin(brng)*Math.sin(d/R)*Math.cos(lat1), 
                 Math.cos(d/R)-Math.sin(lat1)*Math.sin(lat2));

it's all fairly simple except I'm unsure what the comma after cos(lat1) does? I read that in javascript it is used to assign the value after the coma to a variable while still evaluating the first expression, although in the above code the expression before the comma is not stored?

Any help on converting this to java or understanding what the comma does?

The original maths formula also has a comma

φ2 = asin( sin(φ1)*cos(d/R) + cos(φ1)*sin(d/R)*cos(θ) )
 λ2 = λ1 + atan2( sin(θ)*sin(d/R)*cos(φ1), cos(d/R)−sin(φ1)*sin(φ2) )

Answer 1

It's not an operator, it's simply separating the two arguments to atan2 . It's exactly the same in Java.

(Recall that atan2 takes the x and y components separately, in order to resolve rotational ambiguity.)

Answer 2

Math.atan2 method accepts two arguments. Comma simply separates it.

Math.atan2(y, x)

Returns the arctangent of the quotient of its arguments.

Reference:

• https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Math/atan2

Answer 3

The only change required is to give the variables a type.

double lat2 = Math.asin(Math.sin(lat1) * Math.cos(d / R) +
        Math.cos(lat1) * Math.sin(d / R) * Math.cos(brng));
double lon2 = lon1 + Math.atan2(Math.sin(brng) * Math.sin(d / R) * Math.cos(lat1),
        Math.cos(d / R) - Math.sin(lat1) * Math.sin(lat2));