如何在php中引用其他对象？

Question

I'm very new to Php and I'm from Java. I have a class in Java like this:

class A {
}

class B{
}

in same package. Inside class A I have defined a datatype of type B like :

   B bType;

I want the same behavior in php. Is that possible to do so?

And are there any way to "package" my classes in php?

Thanks in advance.

Answer 1

You can use namespaces (which is packaging ). If you really want to package then you should take a look at http://php.net/manual/en/book.phar.php (but I guess til' now, nobody really does that).

You can force types in functions but not for variables.

function (Array $bla, YourClass $test) {
   /** ... **/
}

hope it helps

Answer 2

inside A class define:

$BClass = new B(arguments for contructor);
$BClass = new B; //without contructor

Answer 3

PHP doesn't support static typing but you can use type hinting to define a data-type within a method. For example...

<?php

class A
{
    public function test(B $b) // Must be a method within B or a new exception will be thrown.
    {
        echo 1 + $b->test(); // adds one plus the return value of $b->test() from the B class.
    }
}

class B
{
    public function test() 
    {
        return 1;
    }
}

    class C
    {
         public function test()
         {
              $b = new B; // initializes the B class.
              return $b->test(); // calls the test method within the B class.
         }
    }

$a = new A;
$a->test(new B); // returns 2

You could also use gettype($a) to detect a certain data-type.