如何防止javascript中的非字母数字输入？

Question

$("#user").keyup(function(e){ 
    var regx = /^[A-Za-z0-9]+$/;
    if (!regx.test('#user')) 
    {$("#infoUser").html("Alphanumeric only allowed !");}
);}

#user is a text input, and I want to diplay a warning if user enters anything except letters and numbers.
In the above case, the warning is present whatever is typed.

Answer 1

change:

if (!regx.test('#user')) 

to

if (!regx.test( $(this).val() ) ) 

Do:

$("#user").keyup(function(e){     
    var str = $.trim( $(this).val() );
    if( str != "" ) {
      var regx = /^[A-Za-z0-9]+$/;
      if (!regx.test(str)) {
        $("#infoUser").html("Alphanumeric only allowed !");
      }
    }
    else {
       //empty value -- do something here
    }
});

JS Fiddle example

Answer 2

THis line

regx.test('#user')

has you testing the string #user , and that is a string that has a bad character (the # ). So it will always say not allowed.

Use the actual value of your $("#user") there by using $(this).val()

Answer 3

You must test with #user element value not '#user' string

$("#user").keyup(function(e){ 
    var regx = /^[A-Za-z0-9]+$/;
    if (!regx.test($('#user').val()))  // .
    {$("#infoUser").html("Alphanumeric only allowed !");}
);}

Answer 4

$('#alpha').bind('keypress', function (event) {
var regex = new RegExp("^[a-zA-Z\b]+$");
var key = String.fromCharCode(!event.charCode ? event.which : event.charCode);
if (!regex.test(key)) {
   event.preventDefault();
   return false;
}
});

$('#numeric').bind('keypress', function (event) {
var regex = new RegExp("^[0-9\b]+$");
var key = String.fromCharCode(!event.charCode ? event.which : event.charCode);
if (!regex.test(key)) {
   event.preventDefault();
   return false;
}
});

$('#alphanumeric').bind('keypress', function (event) {
var regex = new RegExp("^[a-zA-Z0-9\b]+$");
var key = String.fromCharCode(!event.charCode ? event.which : event.charCode);
if (!regex.test(key)) {
   event.preventDefault();
   return false;
}
});


$('#alphanumericspecial').bind('keypress', function (event) {
var regex = new RegExp("^[a-zA-Z0-9 .]+$");
var key = String.fromCharCode(!event.charCode ? event.which : event.charCode);
if (!regex.test(key)) {
   event.preventDefault();
   return false;
}
});

Answer 5

   function isNotAlphanumeric(){
        return (! val.match(/^[a-zA-Z]+$/))
        //return val.match(/^[a-zA-Z0-9]+$/) ? false : true;
   } 

so if val is alpha numeric it return false. So based on returned value take appropriate action. You can call this method on key up event.