在Spring中将.jsp映射到Controller

Question

I am just starting with spring so I started with a SpringMVC on Heroku. 我刚刚从春天开始，所以我开始在Heroku上使用SpringMVC。 By choosing the Spring MVC Template in Eclipse I got a very basic Application. 通过在Eclipse中选择Spring MVC模板，我得到了一个非常基本的应用程序。 Now I am trying to modify this. 现在我想修改这个。

However if I create another .jsp and I visit the URL given in the Controller I get an 404, that's pretty clear, because I never mapped the Controller to the .jsp . 但是，如果我创建另一个.jsp并访问Controller中给出的URL，我会得到一个404，这很清楚，因为我从未将Controller映射到.jsp 。 But how should I do this? 但是我该怎么做呢？

Here is everything I changed (Even if I'm not sure that you will need it): 这是我改变的一切（即使我不确定你是否需要它）：

The Controller: 控制者：

@Controller
public class BookingController {

    @Autowired
    BookingService bookingService;

    @RequestMapping("/AvailableBikes")
    public String getAvailableBikes(Model model){
        // TOOD: Fix Date
        int availableBookings = bookingService.getAvailableBookings(Calendar.getInstance().getTime());
        model.addAttribute("NumAvailableBikes", Integer.toString(availableBookings));

        return "NumAvailableBikes";
    }

}

The Entity: 实体：

@Entity
public class Booking {

    @Id
    @GeneratedValue
    private Integer id;


// Lots of getters setters an attributes ...

}

The Service: 服务：

@Service
public class BookingServiceImpl implements BookingService {

    @Override
    public void addBooking(Booking booking) {
        // TODO Auto-generated method stub

    }

    @Override
    public int getAvailableBookings(Date bookingDay) {
        // TODO Auto-generated method stub
        return 12;
    }

    @Override
    public void removeBooking(Booking booking) {
        // TODO Auto-generated method stub
    }

}

booking.jsp: booking.jsp：

<!doctype html>
<%@taglib uri="http://www.springframework.org/tags" prefix="spring"%>
<%@taglib uri="http://www.springframework.org/tags/form" prefix="form"%>
<%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>

<html>
<head>
    <meta charset="utf-8">
    <title>Spring MVC and Hibernate Template</title>

    <meta content="IE=edge,chrome=1" http-equiv="X-UA-Compatible">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">

    <link href="http://twitter.github.com/bootstrap/assets/css/bootstrap.css" rel="stylesheet">
    <link href="http://twitter.github.com/bootstrap/assets/css/bootstrap-responsive.css" rel="stylesheet">

</head>

<body>

Test!

<h2>${NumAvailableBikes}</h2>

</body>

web.xml: web.xml中：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    id="WebApp_ID" version="2.5">
    <display-name>Spring-Hibernate-Template</display-name>

    <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>

    <servlet>
        <servlet-name>spring</servlet-name>
        <servlet-class>
            org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>classpath:applicationContext.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>spring</servlet-name>
        <url-pattern>/booking/*</url-pattern>
    </servlet-mapping>
</web-app>

applicationContext.xml: applicationContext.xml中：

<?xml  version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:jdbc="http://www.springframework.org/schema/jdbc"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
                           http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc.xsd
                           http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
                           http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
                           http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">

    <context:annotation-config />
    <context:component-scan base-package="org.stuttgart.fahrrad" />

    <mvc:annotation-driven/>

    <bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
        <property name="prefix" value="/WEB-INF/jsp/" />
        <property name="suffix" value=".jsp" />
    </bean>

    <tx:annotation-driven />
    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
        <property name="dataSource" ref="dataSource"/>

    </bean>

    <beans profile="default">
        <jdbc:embedded-database id="dataSource"/>        
        <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
            <property name="dataSource" ref="dataSource"/>
            <property name="jpaVendorAdapter">
                <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
            </property>
            <property name="jpaProperties">
                <props>
                    <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop>
                    <prop key="hibernate.hbm2ddl.auto">create</prop>
                </props>
            </property>
        </bean>
    </beans>

    <beans profile="prod">
        <bean class="java.net.URI" id="dbUrl">
            <constructor-arg value="#{systemEnvironment['DATABASE_URL']}"/>
        </bean>

        <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource">
            <property name="url" value="#{ 'jdbc:postgresql://' + @dbUrl.getHost() + @dbUrl.getPath() }"/>
            <property name="username" value="#{ @dbUrl.getUserInfo().split(':')[0] }"/>
            <property name="password" value="#{ @dbUrl.getUserInfo().split(':')[1] }"/>
        </bean>

        <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
            <property name="dataSource" ref="dataSource"/>
            <property name="jpaVendorAdapter">
                <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
            </property>
            <property name="jpaProperties">
                <props>
                    <prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop>
                    <prop key="hibernate.show_sql">true</prop>
                    <!-- change this to 'verify' before running as a production app -->
                    <prop key="hibernate.hbm2ddl.auto">update</prop>
                </props>
            </property>
        </bean>
    </beans>

</beans>

Answer 1

return "NumAvailableBikes"; 返回“NumAvailableBikes”; should be changed to return "booking"; 应改为返回“预订”;

Answer 2

First consider how your dispatcher servlet is configured. 首先考虑如何配置调度程序servlet。 Currently it is mapped to the following url pattern: 目前它映射到以下url模式：

<servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/booking/*</url-pattern>
</servlet-mapping>

This means that only urls which contain the booking directory directly after the context root will be mapped. 这意味着只会映射在上下文根之后直接包含booking目录的URL。 So a url like `contextroot/AvailableBikes' will never get picked up and processed by the dispatcher. 所以像'contextroot / AvailableBikes'这样的网址永远不会被调度员接收和处理。 I would recommend changing your url pattern to: 我建议将您的网址格式更改为：

<servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

This mapping serves as almost a catch all mapping. 此映射几乎可以捕获所有映射。 It will match all urls which are not mapped to another servlet. 它将匹配未映射到另一个servlet的所有URL。 Please note: it will also create the need for you to setup configuration to map static resources such as css and js files. 请注意：它还将使您需要设置配置以映射静态资源，如css和js文件。 This is explained in the Spring documentation. 这在Spring文档中有解释。

Once you have made this change I think you should be able to hit the Controller with a URL like rootcontext/AvailableBikes . 一旦你做了这个改变，我认为你应该能够使用像rootcontext/AvailableBikes这样的URL命中Controller。 Setup a debug point in the controller to confirm. 在控制器中设置调试点以进行确认。 Also note that you will not use a url containing a direct path to the .jsp file but the path specified in the request mapping. 另请注意，您不会使用包含.jsp文件的直接路径的URL，而是使用请求映射中指定的路径。 Your jsp file should be available @ webcontent directory/WEB-INF/jsp/NumAvailableBikes.jsp . 您的jsp文件应该可用@ webcontent directory/WEB-INF/jsp/NumAvailableBikes.jsp 。

In order to display the booking.jsp which should be available @ webcontent dir/WEB-INF/jsp/booking.jsp the controller must be modified to return the String booking. 为了显示应该可用的booking.jsp @ webcontent dir/WEB-INF/jsp/booking.jsp ，必须修改控制器以返回String预订。

   @RequestMapping("/AvailableBikes")
    public String getAvailableBikes(Model model){
        // TOOD: Fix Date
        int availableBookings = bookingService.getAvailableBookings(Calendar.getInstance().getTime());
        model.addAttribute("NumAvailableBikes", Integer.toString(availableBookings));

        return "booking";
    }

在Spring中将.jsp映射到Controller

问题描述

2 个解决方案

解决方案1
3 已采纳 2013-01-16 11:02:15

解决方案2
2 2013-01-16 10:40:56

在Spring中将.jsp映射到Controller

问题描述

2 个解决方案

解决方案1 3 已采纳 2013-01-16 11:02:15

解决方案2 2 2013-01-16 10:40:56

解决方案1
3 已采纳 2013-01-16 11:02:15

解决方案2
2 2013-01-16 10:40:56