[英]LINQ: is there a way to supply a predicate with more than one parameter to where clause
wondering if there is a way to do the following: I basically want to supply a predicate to a where clause with more than one paremeters like the following: 想知道是否有办法执行以下操作:我基本上想要为具有多个参数的where子句提供谓词,如下所示:
public bool Predicate (string a, object obj)
{
// blah blah
}
public void Test()
{
var obj = "Object";
var items = new string[]{"a", "b", "c"};
var result = items.Where(Predicate); // here I want to somehow supply obj to Predicate as the second argument
}
var result = items.Where(i => Predicate(i, obj));
The operation you want is called "partial evaluation"; 您想要的操作称为“部分评估”; it is logically related to "currying" a two-parameter function into two one-parameter functions.
它在逻辑上与将两参数函数“卷曲”成两个单参数函数有关。
static class Extensions
{
static Func<A, R> PartiallyEvaluateRight<A, B, R>(this Func<A, B, R> f, B b)
{
return a => f(a, b);
}
}
...
Func<int, int, bool> isGreater = (x, y) => x > y;
Func<int, bool> isGreaterThanTwo = isGreater.PartiallyEvaluateRight(2);
And now you can use isGreaterThanTwo
in a where
clause. 现在你可以在
where
子句中使用isGreaterThanTwo
。
If you wanted to supply the first argument then you could easily write PartiallyEvaluateLeft
. 如果您想提供第一个参数,那么您可以轻松编写
PartiallyEvaluateLeft
。
Make sense? 合理?
The currying operation (which partially applies to the left) is usually written: currying操作(部分适用于左边)通常写成:
static class Extensions
{
static Func<A, Func<B, R>> Curry<A, B, R>(this Func<A, B, R> f)
{
return a => b => f(a, b);
}
}
And now you can make a factory: 现在你可以做一个工厂:
Func<int, int, bool> greaterThan = (x, y) => x > y;
Func<int, Func<int, bool>> factory = greaterThan.Curry();
Func<int, bool> withTwo = factory(2); // makes y => 2 > y
Is that all clear? 这一切都清楚了吗?
Do you expect something like this 你期待这样的事吗?
public bool Predicate (string a, object obj)
{
// blah blah
}
public void Test()
{
var obj = "Object";
var items = new string[]{"a", "b", "c"};
var result = items.Where(x => Predicate(x, obj)); // here I want to somehow supply obj to Predicate as the second argument
}
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