字符串后的正则表达式php

Question

Hi I have a very long text standard and I want to take a part of a string after a standard string:

$string = "bla bla bla... Refer: my text /n bla bla bla";

I want to take the string: my text . Is ever after Refer: and before a /n or /r . Is possible with a regular expression? I have done this wit substr and strpos but I want to optimize my text.

Answer 1

\\ s表示空格^表示除

preg_match('|.*Refer:\s+([^/n/r]*)|', $string, $out);

Answer 2

preg_match('/Refer:\s+(.*?)$/i', $string, $matches);
echo $matches[0];

Answer 3

$regex = "/.*Refer:(.*?)(?:\/n|\/r)/";
preg_match($regex, $string, $matches);
echo $matches[1];