Android如何在物理按钮上执行反馈触觉？

Question

After checking android source code, I knew the when a button perform click it will call the view's performHapticFeedback methor so that the phone will perform a BZZZTT effect. the performHapticFeedback code is like:

public boolean performHapticFeedback(int feedbackConstant, int flags) {
    if (mAttachInfo == null) {
        return false;
    }
    //noinspection SimplifiableIfStatement
    if ((flags & HapticFeedbackConstants.FLAG_IGNORE_VIEW_SETTING) == 0
            && !isHapticFeedbackEnabled()) {
        return false;
    }
    return mAttachInfo.mRootCallbacks.performHapticFeedback(feedbackConstant,
            (flags & HapticFeedbackConstants.FLAG_IGNORE_GLOBAL_SETTING) != 0);
}

But, I wonder how android performs a feedback haptic on physical button (such as key_home,key_Back,key_menu). cause the physical button doesn't base on View. I have searched the source code for a whole afternoon but I got nothing valuable code lines about how physical button performs Haptic Feedback~~~~ Can anyone give me some tips?

Thanks

Answer 1

The relative code lines are found in PhoneWindowManager.java -> public int interceptKeyBeforeQueueing(KeyEvent event, int policyFlags, boolean isScreenOn) .(which is called before the other uplever apps can handle); After judging on KeyEvent code, then it will call the mVibrator.vibrate(pattern[0]); in which the mVibrator is got by calling mVibrator = (Vibrator)context.getSystemService(Context.VIBRATOR_SERVICE);