静态常量数组

Question

If I read this in a class as a data member, is the static referring to the entire expression (the array itself) or the elements of the array?

static const int* array[100];

Is the array, array , static, or does the array contain 100 static const int pointers ?

I'm assuming the former, but the way the word const changes meaning makes me wonder if static also changes meaning based on where in the expression it exists. In the above, the pointer array is not const yet the elements of the array are const , so I wonder if the pointer of the array is static .

Answer 1

C++11 7.1.1 Storage class specifiers:
§5

The static specifier can be applied only to names of variables and functions and to anonymous unions (9.5). There can be no static function declarations within a block, nor any static function parameters. A static specifier used in the declaration of a variable declares the variable to have static storage duration (3.7.1), unless accompanied by the thread_local specifier, which declares the variable to have thread storage duration (3.7.2). A static specifier can be used in declarations of class members; 9.4 describes its effect. For the linkage of a name declared with a static specifier, see 3.5.

So what are you declaring in the code example?

static const int* array[100];

Obviously, you are declaring the variable array So the static applies to array .
Do not confuse storage class specifier with cv-qualifiers the former applies to the variable being declared while the latter applies to the type .

Answer 2

static , extern and register apply to the variable you declare, to array in this example.

So, you get a static array of 100 pointers to constant integers.