[英]returning value from ajax, back to the JS function that it
here is the problem. 这是问题所在。
i have HTML Form
and it has a button submit
with an onclick=validationFunction()
. 我有
HTML Form
,并且有一个带有onclick=validationFunction()
的按钮submit
。 When i click this button, values from form goes to this function. 当我单击此按钮时,表单中的值将转到此功能。
Now, in this function, the values of the form are che enter code here
cked if enter code here
they are correct or not. 现在,在此函数中,如果
enter code here
正确或错误,则enter code here
表单的值。 In addition, it has 1 input Field
who has to be checked for validation, and also checked again from database to see it that value exists there. 此外,它具有1个
input Field
,必须检查该input Field
以进行验证,并且还再次从数据库中检查该字段是否存在值。 This part is done via ajax
. 这部分是通过
ajax
完成的。 Below the ajax call, there is a return value (boolen)
for the function validationFucntion()
. 在ajax调用下方,有一个函数
validationFucntion()
的返回值(boolen)
值validationFucntion()
。
Now, what i want. 现在,我想要什么。 i want either of the two things.
我想要两件事之一。
1) ajax should return true or false within its success
1)ajax在
success
内应返回true或false
2) or ajax should send the value just below where the ajax call ends. 2)或ajax应该在ajax调用结束处的下面发送该值。 By now, im failing big times to do either of the things.
到现在为止,即时通讯无法成功完成这两项工作。
Here is a sample pseudo code. 这是示例伪代码。
function validationFunction()
{
validations checks in progress
$.ajax({
url:'checkIfNumberExists.php',
data : {
'number : num //this num is coming from above
},
method:'GET',
success: function(data)
{
console.log("Return Value = "+this.toReturn);
if( (this.toReturn) > 0 )
{
either return validationFunction from here or set a flag.
}
else
{
either return validationFunction from here or set a flag.
}
});
}
checkIfNumberExists.php checkIfNumberExists.php
<?php
$num = $_GET['number'];
$toReturn = 0 ;
$queryCheckNo = mysql_query('SELECT * FROM `TABLE` WHERE `number_from_table`="'.$num.'" ');
while($row = mysql_fetch_assoc($queryCheckNo)){
$toReturn++;
}
echo ($toReturn);
?>
try this plug in 试试这个插件
<script>
// wait for the DOM to be loaded
$(document).ready(function()
{
// bind 'myForm' and provide a simple callback function
$("#tempForm").ajaxForm({
url:'../calling action or servlet',
type:'post',
beforeSend:function()
{
alert("perform action before making the ajax call like showing spinner image");
},
success:function(e){
alert("data is"+e);
alert("now do whatever you want with the data");
}
});
});
</script>
and keep this inside your form 并将其保留在您的表单中
<form id="tempForm" enctype="multipart/form-data">
<input type="file" name="" id="" />
</form>
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