ruby正则表达式，以gsub为字符串的特定部分
[英]ruby regular expression to gsub a particular portion of a string
问题描述
How to gsub a sub-string that starts with a particular character or enclosed by particular characters in ruby? 
如何gsub一个以特定字符starts with或enclosed by ruby中的特定字符enclosed by的子字符串？
As for example :input is : Prime rates[ US Effective Date: 12/16/2008 ] I want to gsub the sub-string that is enclosed by two square braces [ and ] and want output like : Prime Rates 例如：输入为： Prime rates[ US Effective Date: 12/16/2008 ]我想gsub由两个方括号[和]括起来的子字符串，并希望输出如下： Prime Rates
How can I do that using ruby regular expression? 我怎么能用ruby正则表达式做到这一点？
1 个解决方案
解决方案1
3 已采纳 2013-01-21 20:55:07
Maybe something like: 也许是这样的：
s.gsub(/\[.*\]/, "")
This will remove anything enclosed in [] assuming there is no more than one occurrence of such substring. 这将删除[]包含的任何内容，假设此类子字符串不会出现多于一次。
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