node.js shell 命令执行

Question

I am still trying to grasp the finer points of how I can run a linux or windows shell command and capture output within node.js; ultimately, I want to do something like this...

//pseudocode
output = run_command(cmd, args)

The important piece is that output must be available to a globally scoped variable (or object). I tried the following function, but for some reason, I get undefined printed to the console...

function run_cmd(cmd, args, cb) {
  var spawn = require('child_process').spawn
  var child = spawn(cmd, args);
  var me = this;
  child.stdout.on('data', function(me, data) {
    cb(me, data);
  });
}
foo = new run_cmd('dir', ['/B'], function (me, data){me.stdout=data;});
console.log(foo.stdout);  // yields "undefined" <------

I'm having trouble understanding where the code breaks above... a very simple prototype of that model works...

function try_this(cmd, cb) {
  var me = this;
  cb(me, cmd)
}
bar = new try_this('guacamole', function (me, cmd){me.output=cmd;})
console.log(bar.output); // yields "guacamole" <----

Can someone help me understand why try_this() works, and run_cmd() does not? FWIW, I need to use child_process.spawn , because child_process.exec has a 200KB buffer limit.

Final Resolution

I'm accepting James White's answer, but this is the exact code that worked for me...

function cmd_exec(cmd, args, cb_stdout, cb_end) {
  var spawn = require('child_process').spawn,
    child = spawn(cmd, args),
    me = this;
  me.exit = 0;  // Send a cb to set 1 when cmd exits
  me.stdout = "";
  child.stdout.on('data', function (data) { cb_stdout(me, data) });
  child.stdout.on('end', function () { cb_end(me) });
}
foo = new cmd_exec('netstat', ['-rn'], 
  function (me, data) {me.stdout += data.toString();},
  function (me) {me.exit = 1;}
);
function log_console() {
  console.log(foo.stdout);
}
setTimeout(
  // wait 0.25 seconds and print the output
  log_console,
250);

Answer 1

There are three issues here that need to be fixed:

First is that you are expecting synchronous behavior while using stdout asynchronously. All of the calls in your run_cmd function are asynchronous, so it will spawn the child process and return immediately regardless of whether some, all, or none of the data has been read off of stdout. As such, when you run

console.log(foo.stdout);

you get whatever happens to be stored in foo.stdout at the moment, and there's no guarantee what that will be because your child process might still be running.

Second is that stdout is a readable stream , so 1) the data event can be called multiple times, and 2) the callback is given a buffer, not a string. Easy to remedy; just change

foo = new run_cmd(
    'netstat.exe', ['-an'], function (me, data){me.stdout=data;}
);

into

foo = new run_cmd(
    'netstat.exe', ['-an'], function (me, buffer){me.stdout+=buffer.toString();}
);

so that we convert our buffer into a string and append that string to our stdout variable.

Third is that you can only know you've received all output when you get the 'end' event, which means we need another listener and callback:

function run_cmd(cmd, args, cb, end) {
    // ...
    child.stdout.on('end', end);
}

So, your final result is this:

function run_cmd(cmd, args, cb, end) {
    var spawn = require('child_process').spawn,
        child = spawn(cmd, args),
        me = this;
    child.stdout.on('data', function (buffer) { cb(me, buffer) });
    child.stdout.on('end', end);
}

// Run C:\Windows\System32\netstat.exe -an
var foo = new run_cmd(
    'netstat.exe', ['-an'],
    function (me, buffer) { me.stdout += buffer.toString() },
    function () { console.log(foo.stdout) }
);

Answer 2

A simplified version of the accepted answer (third point), just worked for me.

function run_cmd(cmd, args, callBack ) {
    var spawn = require('child_process').spawn;
    var child = spawn(cmd, args);
    var resp = "";

    child.stdout.on('data', function (buffer) { resp += buffer.toString() });
    child.stdout.on('end', function() { callBack (resp) });
} // ()

Usage:

run_cmd( "ls", ["-l"], function(text) { console.log (text) });

run_cmd( "hostname", [], function(text) { console.log (text) });

Answer 3

I used this more concisely :

var sys = require('sys')
var exec = require('child_process').exec;
function puts(error, stdout, stderr) { sys.puts(stdout) }
exec("ls -la", puts);

it works perfectly. :)

Answer 4

Simplest way is to just use the ShellJS lib ...

$ npm install [-g] shelljs

EXEC Example:

require('shelljs/global');

// Sync call to exec()
var version = exec('node --version', {silent:true}).output;

// Async call to exec()
exec('netstat.exe -an', function(status, output) {
  console.log('Exit status:', status);
  console.log('Program output:', output);
});

ShellJs.org supports many common shell commands mapped as NodeJS functions including:

• cat
• cd
• chmod
• cp
• dirs
• echo
• exec
• exit
• find
• grep
• ln
• ls
• mkdir
• mv
• popd
• pushd
• pwd
• rm
• sed
• test
• which

Answer 5

I had a similar problem and I ended up writing a node extension for this. You can check out the git repository. It's open source and free and all that good stuff !

https://github.com/aponxi/npm-execxi

ExecXI is a node extension written in C++ to execute shell commands one by one, outputting the command's output to the console in real-time. Optional chained, and unchained ways are present; meaning that you can choose to stop the script after a command fails (chained), or you can continue as if nothing has happened !

Usage instructions are in the ReadMe file . Feel free to make pull requests or submit issues!

I thought it was worth to mention it.

Answer 6

@TonyO'Hagan is comprehrensive shelljs answer, but, I would like to highlight the synchronous version of his answer:

var shell = require('shelljs');
var output = shell.exec('netstat -rn', {silent:true}).output;
console.log(output);

Answer 7

Synchronous one-liner:

require('child_process').execSync("echo 'hi'", function puts(error, stdout, stderr) {
  console.log(stdout) 
});

Answer 8

There's a variable conflict in your run_cmd function:

  var me = this;
  child.stdout.on('data', function(me, data) {
    // me is overriden by function argument
    cb(me, data);
  });

Simply change it to this:

  var me = this;
  child.stdout.on('data', function(data) {
    // One argument only!
    cb(me, data);
  });

In order to see errors always add this:

  child.stderr.on('data', function(data) {
      console.log( data );
  });

EDIT You're code fails because you are trying to run dir which is not provided as a separate standalone program. It is a command in cmd process. If you want to play with filesystem use native require( 'fs' ) .

Alternatively ( which I do not recommend ) you can create a batch file which you can then run. Note that OS by default fires batch files via cmd .

Answer 9

You're not actually returning anything from your run_cmd function.

function run_cmd(cmd, args, done) {
    var spawn = require("child_process").spawn;
    var child = spawn(cmd, args);
    var result = { stdout: "" };
    child.stdout.on("data", function (data) {
            result.stdout += data;
    });
    child.stdout.on("end", function () {
            done();
    });
    return result;
}

> foo = run_cmd("ls", ["-al"], function () { console.log("done!"); });
{ stdout: '' }
done!
> foo.stdout
'total 28520...'

Works just fine. :)

Answer 10

A promisified version of the most-awarded answer:

  runCmd: (cmd, args) => {
    return new Promise((resolve, reject) => {
      var spawn = require('child_process').spawn
      var child = spawn(cmd, args)
      var resp = ''
      child.stdout.on('data', function (buffer) { resp += buffer.toString() })
      child.stdout.on('end', function () { resolve(resp) })
    })
  }

To use:

 runCmd('ls').then(ret => console.log(ret))