具有多个选择字段的搜索表单

Question

I have made search form, where are list menus. it works very well if I fill every field of the form but, I want that all the fields work independently, like if you fill only one field it must show the result which is about this field only, and if you choos another field it must give seemlier result. my code looks like this. thank you beforehand.

 <?php 
 mysql_query("SET NAMES UTF8");
 $mxare = mysql_real_escape_string($_POST['mxare']);
 $raioni = mysql_real_escape_string($_POST['raioni']);
 $type = mysql_real_escape_string($_POST['type']);
 $result = mysql_query("SELECT * FROM dzeglebi WHERE mxare = '$mxare' AND   
 raioni ='$raioni' AND  type = '$type' ORDER BY title ASC", $db); 
 $myrow = mysql_fetch_array($result);

Answer 1

based on your data, you can try like following

$mxare = mysql_real_escape_string($_POST['mxare']);
$raioni = mysql_real_escape_string($_POST['raioni']);
$type = mysql_real_escape_string($_POST['type']);

// here 
$sql = "SELECT * FROM dzeglebi WHERE 1==1 " ;
if ( isset($mxare)) $sql = $sql . " AND " . " mxare = '$mxare'";
if ( isset($raioni)) $sql = $sql . " AND " . " raioni= '$raioni'";
.....
.....

$result = mysql_query($sql)
$myrow = mysql_fetch_array($result);

Answer 2

You can try this;

$where = array("1=1");
if (!empty($_POST["field_1"])) {
    $where[] = sprintf("field_1='%s'", mysql_real_escape_string($_POST["field_1"]));
}
// if (!empty($_POST["field_2"])) {
// and so on...

// convert where to string with AND or OR
$where = join(" AND ", $where);
mysql_query("SELECT * FROM dzeglebi WHERE $where");