如何将十进制字符串更改为十六进制格式的字符串？

Question

How do I change a decimal string like 123456789 to a hex formatted string like this: 如何将十进制字符串（如123456789更改为十六进制格式的字符串，如下所示：

07:5B:CD:15

I have looked at the hex function, but it doesn't give me the above format. 我已经看过hex函数，但是它没有给出上述格式。

UPDATED 更新

I would also like -123456789 to be: 我也希望-123456789是：

-07:5B:CD:15

rather than 而不是

-7:5B:CD:15

Answer 1

s = '123456789'
a = '{:08X}'.format(int(s))
print ':'.join(a[i:i+2] for i in xrange(0, len(a), 2))

prints 版画

07:5B:CD:15