获取Android网络接口IP地址

Question

I am writing a wifi-direct application for Android. I am trying to make a socket connection to a device. Since the group owner intent function doesn't seem to work (it just assigns randomly it appears) I have to find a way to transfer the clients IP address to the host. The only address I know of is the host device which comes in the group info object that WifiP2pManager can get me. I know which device is the host and which one is the client so I can open a socket for a connection to arrive or attempt to connect to the other one.

What I need to do is find a way to transfer the device's IP address of the Wifi P2P (Wifi Direct) client if the 'host' device is the group owner. If the host is the group owner, I have no way to connect to the socket on the client. It's a bit confusing but that's how it works.

I've seen things like get the IP address from the ARP table, but the ARP table seems to clear itself after only a few seconds (like a minute) and on ICS since the wifi interface is disabled for Wifi direct I don't even see anything in the arp table.

I feel like this should be easy but I'm not a big linux user so I don't know what file would hold the network interface configurations. Is there a way to get hte IP addresses of network interfaces? Or at least the Wifi P2P interface? (Note: This is not the wifi address. It's similar to the tethering address except it's Wifi Direct. WifiManager does not return this)

Thanks,
Mgamerz

Answer 1

DhcpInfo dhcpInfo = (WifiManager)this.context.getSystemService(Context.WIFI_SERVICE)).getDhcpInfo();
String ipaddress = intToIp(dhcpInfo.ipAddress)

intToIp(int integer) {
        return (integer & 0xFF) + "." + ((integer >> 8) & 0xFF) + "."
                + ((integer >> 16) & 0xFF) + "." + ((integer >> 24) & 0xFF);
    }

Above code should help you get the ipaddress...

to get the ip address of the client who is connecting to host through a socket you may use.. clientSocket = this.serverSocket.accept(); clientSocket.getInetAddress();