Spring Hibernate：org.hibernate.exception.SQLGrammarException
[英]Spring hibernate: org.hibernate.exception.SQLGrammarException
问题描述
My DAO layer code is as follows: 
我的DAO层代码如下：
package com.app.dao;
import javax.annotation.Resource;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.springframework.orm.hibernate3.HibernateTemplate;
import org.springframework.orm.hibernate3.support.HibernateDaoSupport;
import org.springframework.stereotype.Repository;
import com.app.pojo.InterviewerPojo;
@Repository("interviewer_details_dao")
public class InterviewerDetailsDaoImpl implements InterviewerDetailsDao {
@Resource(name="sessionFactory")
private SessionFactory factory;
/*private HibernateTemplate template;
public void setSessionFactory(){
template = new HibernateTemplate(factory);
}*/
/*private HibernateTemplate template = new HibernateTemplate(sessionFactory);*/
@Override
public void saveInterviewDetails(InterviewerPojo interviewerPojo) {
/* Session sess = factory.getCurrentSession();
try{
sess.getTransaction().wasCommitted();
Transaction trans = sess.beginTransaction();
System.out.println("a");
sess.saveOrUpdate(interviewerPojo);
sess.getTransaction().commit();}
catch(Exception e){
throw e;
}*/
System.out.println("b");
factory.getCurrentSession().save(interviewerPojo);
/* System.out.println(interviewerPojo);
template.saveOrUpdate(interviewerPojo);
System.out.println("b");*/
System.out.println("done");
}
}
the same code as above was running if i am getting the values from database as follows sessionFactory.getCurrentSession().createQuery("select m from emp m).list; But as I writing another page to insert values then it is having problem * As you can see i used same concept, I populated MODEL(POJO) class by another MODEL(pojo) which i have taken from database by above query * and now debugging goes upto "template.saveOrUpdate" and throws exception as follows 如果我要从数据库中获取值，则运行与上述相同的代码，如下所示： sessionFactory.getCurrentSession（）。createQuery（“从emp m中选择m）.list; 但是，当我编写另一页来插入值时，则出现了问题 * 如您所见，我使用了相同的概念，我通过上面的查询 * 从数据库获取的另一个MODEL（pojo）填充了MODEL（POJO）类 ，现在调试升至“ template.saveOrUpdate”并抛出异常，如下所示
org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax;
POJO source code: POJO源代码：
package com.app.pojo;
import java.io.Serializable;
import javax.persistence.*;
@SuppressWarnings("serial")
@Entity @Table(name="interviewer")
public class InterviewerPojo implements Serializable {
private int eid;
private int vid;
@Id @GeneratedValue(strategy=GenerationType.SEQUENCE)
private int i_eid;
private String i_name;
private String password;
public int getEid() {
return eid;
}
public void setEid(int eid) {
this.eid = eid;
}
}
Hibernate config: 休眠配置：
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop>
<prop key="hibernate.formatsql">true</prop>
<prop key="hibernate.showsql">true</prop>
<prop key="hibernate.hbm2ddl.auto">validate</prop>
</props>
</property>
1 个解决方案
解决方案1
1 2013-01-28 10:53:30
In your error log, it showed that you're using MySQL. 在错误日志中，它表明您正在使用MySQL。 However, you configured Hibernate dialect was HSQLDialect. 但是，您配置的Hibernate方言是HSQLDialect。
org.hibernate.dialect.HSQLDialect
You should remove this dialect property, Hibernate can automatically detect the right dialect through JDBC driver. 您应该删除该方言属性，Hibernate可以通过JDBC驱动程序自动检测正确的方言。 Or you modify to the correct dialect on your own. 或者您自己修改为正确的方言。
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