如何获取代码行以接受单引号

Question

Because of a single quote I am receiving a expecting ) after argument list error:

window.top.stopAudioUpload(1, '43', 'Thorne, Grandma's Goodbye excerpt.m4a');

audioupload.php (line 11, col 54)

My question is how can I get the line of code to accept single quote?

Code:

 <script language="javascript" type="text/javascript">
 window.top.stopAudioUpload(<?php echo $result; ?>, '<?php echo $id; ?>', '<?php echo $_FILES['fileAudio']['name'] ?>');
 </script>  

Answer 1

Try this:

<script type="text/javascript">
top.stopAudioUpload(
  <?php echo json_encode($result); ?>,
  <?php echo json_encode($id); ?>,
  <?php echo json_encode($_FILES['fileAudio']['name']); ?>
);
</script>

Note the lack of quotes - this is important, because json_encode will add these automatically if needed.

Answer 2

尝试\\逃脱字符“祖母，索恩的再见摘录.m4a”

Answer 3

You could try to manually escape your single-quote with a backslash Thorn, Grandma\\'s Goodbye excerpt.m4a or you could use the escape function - see the docs here:

http://www.php.net/manual/en/function.htmlspecialchars.php

Answer 4

Your issue lies here:

window.top.stopAudioUpload(<?php echo $result; ?>, '<?php echo $id; ?>', '<?php echo $_FILES['fileAudio']['name'] ?>');

Changing the single quotes around '<?php echo will fix it. So:

window.top.stopAudioUpload("<?php echo $result; ?>", "<?php echo $id; ?>", "<?php echo $_FILES['fileAudio']['name'] ?>");

You can also use json_encode($_FILES['fileAudio']['name']) . This adds quotes automatically.