Python-创建支持用户输入的链接列表

Question

Extracted href attributes with BeautifulSoup4 (also using urllib2, webbrowser)... I would like an output similar to this, that supports user input:

Any ideas?

(0) - http://www.example1.com
(1) - http://www.example2.com
(2) - http://www.example3.com
(3) - http://www.example4.com
(4) - http://www.example5.com
(5) - http://www.example6.com

>>> 0 (opens http://www.example1.com in browser)
>>> 1 (opens http://www.example2.com in browser)

Answer 1

You could write your links to an html file, and use something like os.popen('firefox file.html') to open the file so that the user might click the links directly, or you could use the raw_input() function to ask the user for some option, and then call firefox (or other browser) with command line arguments, again using os.popen() .

This worked for me (an example only):

import os

link1 = 'www.google.com'
link2 = 'www.yahoo.com'

s = raw_input("1 = %s\n2 = %s\n\n" % (link1, link2))

if s == '1':
    os.popen("firefox %s" % link1)
elif s == '2':
    os.popen("firefox %s" % link2)